<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD JATS (Z39.96) Journal Publishing DTD v1.3 20210610//EN" "https://jats.nlm.nih.gov/publishing/1.3/JATS-journalpublishing1-3.dtd"><article xml:lang="en" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:ali="http://www.niso.org/schemas/ali/1.0/" dtd-version="1.3" article-type="research-article"><front><journal-meta><journal-id journal-id-type="issn">2460-0245</journal-id><journal-title-group><journal-title>Journal of the Indonesian Mathematical Society</journal-title><abbrev-journal-title>JIMS</abbrev-journal-title></journal-title-group><issn pub-type="epub">2460-0245</issn><issn pub-type="ppub">2086-8952</issn><publisher><publisher-name>IndoMS</publisher-name></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.22342/jims.v32i2.2229</article-id><article-categories><subj-group><subject>From Equations to Action: Mathematical Models Driving Epidemics Control Strategies</subject></subj-group></article-categories><title-group><article-title>Two Different Types Predator with Two Preys</article-title></title-group><contrib-group><contrib contrib-type="author"><name><surname>Krishika</surname><given-names>M.</given-names></name><address><country country="IN">India</country><email>krishika561999@gmail.com</email></address><xref ref-type="aff" rid="AFF-1"></xref><xref ref-type="corresp" rid="cor-0"></xref></contrib><contrib contrib-type="author"><name><surname>Vijaya</surname><given-names>S.</given-names></name><address><country country="IN">India</country><email>krishika561999@gmail.com</email></address><xref ref-type="aff" rid="AFF-1"></xref></contrib></contrib-group><contrib-group><contrib contrib-type="editor"><name><surname>Fitriyati</surname><given-names>Nina</given-names></name><address><email>nina.fitriyati@uinjkt.ac.id</email></address><xref ref-type="aff" rid="EDITOR-AFF-1"></xref></contrib></contrib-group><aff id="AFF-1"><institution content-type="dept">Department of Mathematics</institution><institution-wrap><institution>Annamalai University</institution><institution-id institution-id-type="ror">https://ror.org/01x24z140</institution-id></institution-wrap><country country="IN">India</country></aff><aff id="EDITOR-AFF-1"><institution-wrap><institution>Universidad Insurgentes</institution><institution-id institution-id-type="ror">https://ror.org/04qm2hq24</institution-id></institution-wrap><country country="MX">Mexico</country></aff><author-notes><corresp id="cor-0">Corresponding author: M. Krishika. Email: <email>krishika561999@gmail.com</email></corresp></author-notes><pub-date date-type="pub" iso-8601-date="2026-06-30" publication-format="electronic"><day>30</day><month>06</month><year>2026</year></pub-date><pub-date date-type="collection" iso-8601-date="2026-04-23" publication-format="electronic"><day>23</day><month>04</month><year>2026</year></pub-date><volume>32</volume><issue>2</issue><issue-title>JUNE</issue-title><fpage>1</fpage><lpage>17</lpage><history><date date-type="received" iso-8601-date="2025-09-04"><day>04</day><month>09</month><year>2025</year></date><date date-type="accepted" iso-8601-date="2026-02-08"><day>08</day><month>02</month><year>2026</year></date></history><permissions><copyright-statement>Copyright (c) 2026 Journal of the Indonesian Mathematical Society</copyright-statement><copyright-year>2026</copyright-year><copyright-holder>Journal of the Indonesian Mathematical Society</copyright-holder><license xlink:href="https://creativecommons.org/licenses/by-nc-nd/4.0/"><ali:license_ref xmlns:ali="http://www.niso.org/schemas/ali/1.0/">https://creativecommons.org/licenses/by-nc-nd/4.0/</ali:license_ref><license-p>This work is licensed under a Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License.</license-p></license></permissions><self-uri xlink:href="https://jims-a.org/index.php/jimsa/article/view/2229" xlink:title="2229"></self-uri><abstract><p>This study proposes a mathematical model involving two prey species and two predator types, where only the first prey species benefits from a refuge. The specialist predator is subjected to non-constant harvesting, reflecting fluctuating exploitation pressure. Species interactions follow a Holling type II functional response. The analysis shows that the model is bounded and identifies the equilibrium points along with their stability. Numerical results are illustrated.</p></abstract><kwd-group><kwd>Generalist</kwd><kwd>specialist</kwd><kwd>Lotka-Volterra</kwd><kwd>refuge</kwd><kwd>harvesting</kwd></kwd-group><funding-group><funding-statement>No funding was received for this work.</funding-statement></funding-group><custom-meta-group><custom-meta><meta-name>File created by JATS Editor</meta-name><meta-value>https://jatseditor.com</meta-value></custom-meta><custom-meta><meta-name>issue-created-year</meta-name><meta-value>2026</meta-value></custom-meta></custom-meta-group></article-meta></front><body><sec id="sec-1"><title>1. INTRODUCTION</title><p>Prey-predator interactions play a central role in ecological systems and form an important area of research in mathematical ecology. Various mathematical models have been developed to understand the dynamics of interacting species and the factors afecting their coexistence and stability [<xref ref-type="bibr" rid="BIBR-1">1</xref>, <xref ref-type="bibr" rid="BIBR-2">2</xref>].</p><p>Models involving multiple predator species have received considerable attention because they help explain competition and resource sharing mechanisms among predators. Tansky <xref ref-type="bibr" rid="BIBR-3">[3]</xref> investigated the efects of predator switching, while Hsu and Hubbell <xref ref-type="bibr" rid="BIBR-4">[4]</xref> analyzed competition between predators sharing common prey resources. Kirlinger [?] established conditions for the permanence of species in a two-predator two-prey system. Subsequently, Bhattacharyya and Mukhopadhyay <xref ref-type="bibr" rid="BIBR-5">[5]</xref> incorporated spatial migration and predator switching into prey-predator dynamics and Hadziabdic et al. <xref ref-type="bibr" rid="BIBR-6">[6]</xref> further examined the behavior of Lotka-Volterra systems with two predators and one prey.</p><p>Prey refuge is another important ecological mechanism that allows prey populations to avoid predation by utilizing protected habitats. Ma et al. <xref ref-type="bibr" rid="BIBR-7">[7]</xref> demonstrated that prey refuges significantly influence predator-prey interactions and functional responses. Ko and Ryu <xref ref-type="bibr" rid="BIBR-8">[8]</xref> showed that the incorporation of a constant prey refuge can enhance the stability of predator-prey systems. Li et al. <xref ref-type="bibr" rid="BIBR-9">[9]</xref> further analyzed a predator-prey model with prey refuge and discussed its efects on the long-term dynamics and stability of populations. Recent studies have also explored the combined efects of refuge and other ecological factors on predator-prey interactions [<xref ref-type="bibr" rid="BIBR-10">10</xref>, <xref ref-type="bibr" rid="BIBR-11">11</xref>].</p><p>Harvesting is another factor that strongly influences population dynamics. In natural and managed ecosystems, harvesting rates often vary with environmental conditions, seasonal changes and human activities. Dieci and Rebaza <xref ref-type="bibr" rid="BIBR-12">[12]</xref> investigated dynamical transitions in nonlinear systems, while Leard et al. <xref ref-type="bibr" rid="BIBR-13">[13]</xref> studied ratio-dependent predator-prey models with non-constant harvesting and demonstrated its impact on population stability and persistence.</p><p>Motivated by these studies, the present work proposes a prey-predator model consisting of two predator species, a prey refuge for the first prey population, and non-constant harvesting of the specialist predator. The objective is to investigate the dynamical behavior of the system and analyze the stability characteristics of the interacting populations.</p></sec><sec id="sec-2"><title>2. MATHEMATICAL MODELING</title><p>The prey populations follow logistic growth and grow rapidly when small but slow down near their carrying capacities. They interact with predators based on prey availability. A prey refuge protects a fixed proportion <inline-formula><tex-math id="math-1"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat { m } k _ { 1 } \end{document} ]]></tex-math></inline-formula> of the population, leaving only <inline-formula><tex-math id="math-2"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle ( 1 - \hat { m } ) k _ { 1 } \end{document} ]]></tex-math></inline-formula> exposed to predation. The system includes a specialist predator <inline-formula><tex-math id="math-3"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k _ { 3 } \end{document} ]]></tex-math></inline-formula>, which feeds on a limited prey type, and a generalist predator <inline-formula><tex-math id="math-4"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k _ { 4 } \end{document} ]]></tex-math></inline-formula>, which consumes a wider range of prey. It also incorporates non-constant harvesting, where harvesting rates vary with time, population size, or environmental conditions. The corresponding mathematical formulation and its interaction represention are given below:</p><disp-formula id="equation-1"><tex-math id="math-5"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \left\{ \begin{array}{l l} \frac {d k _ {1}}{d t} & = k _ {1} w _ {1} \left(1 - \frac {k _ {1}}{v _ {1}}\right) - \frac {l _ {1} (1 - \hat {m}) k _ {1} k _ {4}}{(k _ {1} (1 - \hat {m}) + j)}, \\ \frac {d k _ {2}}{d t} & = k _ {2} w _ {2} \left(1 - \frac {k _ {2}}{v _ {2}}\right) - \frac {l _ {2} k _ {2} k _ {3}}{(k _ {2} + j)} - \frac {l _ {3} k _ {2} k _ {4}}{(k _ {2} + j)}, \\ \frac {d k _ {3}}{d t} & = - c _ {1} k _ {3} + \frac {n _ {1} l _ {2} k _ {2} k _ {3}}{(k _ {2} + j)} - \hat {h} _ {1} k _ {3}, \\ \frac {d k _ {4}}{d t} & = - c _ {2} k _ {4} + \frac {n _ {2} l _ {1} (1 - \hat {m}) k _ {1} k _ {4}}{(k _ {1} (1 - \hat {m}) + j)} + \frac {\tilde {n} _ {3} \tilde {l} _ {3} k _ {2} k _ {4}}{(k _ {2} + \tilde {j})}. \end{array} \right.\tag{1} \end{document} ]]></tex-math></disp-formula><table-wrap id="table-1"><label>Table 1</label><caption><p>Biological Description of the parameters for <xref ref-type="disp-formula" rid="equation-1">(1)</xref></p></caption><table><colgroup><col></col><col></col></colgroup><thead><tr><th scope="col">Parameters</th><th scope="col">Description</th></tr></thead><tbody><tr><td><inline-formula><tex-math id="math-6"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_1 \end{document} ]]></tex-math></inline-formula></td><td>Prey population with refuge.</td></tr><tr><td><inline-formula><tex-math id="math-7"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_2 \end{document} ]]></tex-math></inline-formula></td><td>Prey population.</td></tr><tr><td><inline-formula><tex-math id="math-8"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_3 \end{document} ]]></tex-math></inline-formula></td><td>Specialized predator population.</td></tr><tr><td><inline-formula><tex-math id="math-9"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_4 \end{document} ]]></tex-math></inline-formula></td><td>Generalist predator population.</td></tr><tr><td><inline-formula><tex-math id="math-10"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle w_1, w_2 \end{document} ]]></tex-math></inline-formula></td><td>Intrinsic growth rate.</td></tr><tr><td><inline-formula><tex-math id="math-11"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle v_1, v_2 \end{document} ]]></tex-math></inline-formula></td><td>Carrying capacity.</td></tr><tr><td><inline-formula><tex-math id="math-12"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle l_1, l_2, l_3 \end{document} ]]></tex-math></inline-formula></td><td>Rate of predation.</td></tr><tr><td><inline-formula><tex-math id="math-13"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle a \end{document} ]]></tex-math></inline-formula></td><td>Death rate of adult.</td></tr><tr><td><inline-formula><tex-math id="math-14"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle l_1, l_2 \end{document} ]]></tex-math></inline-formula></td><td>Rate of predation.</td></tr><tr><td><inline-formula><tex-math id="math-15"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle n_1, n_2, n_3 \end{document} ]]></tex-math></inline-formula></td><td>Natality rate of predators by each individual.</td></tr><tr><td><inline-formula><tex-math id="math-16"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle j \end{document} ]]></tex-math></inline-formula></td><td>Half saturation constant.</td></tr><tr><td><inline-formula><tex-math id="math-17"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle c_1, c_2 \end{document} ]]></tex-math></inline-formula></td><td>Death rate of predator's</td></tr><tr><td><inline-formula><tex-math id="math-18"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{h}_1 \end{document} ]]></tex-math></inline-formula></td><td>Non constant harvesting rate.</td></tr><tr><td><inline-formula><tex-math id="math-19"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat { m } \end{document} ]]></tex-math></inline-formula></td><td>Refuge proportion <inline-formula><tex-math id="math-20"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle (0<\hat{m}\leq1). \end{document} ]]></tex-math></inline-formula></td></tr></tbody></table></table-wrap><fig id="figure-1"><label>Figure 1.</label><caption><p>Interaction structure of the prey predator model <xref ref-type="disp-formula" rid="equation-1">(1)</xref></p></caption><graphic xlink:href="https://jims-a.org/index.php/jimsa/article/download/2229/544/13876" mime-subtype="png" mimetype="image"><alt-text>Figure 1.</alt-text></graphic></fig></sec><sec id="sec-3"><title>3.   POSITIVE AND BOUNDEDNESS</title><p>The positivity and boundedness properties ensure that all species populations remain non-negative and finite over time. Ecologically, this reflects that populations cannot be negative and are limited by resources and environmental constraints, keeping the model biologically realistic.</p><p><bold>Theorem 3.1. </bold><italic>All solution of the system </italic><xref ref-type="disp-formula" rid="equation-1">(1)</xref><italic> initiating from </italic><inline-formula><tex-math id="math-21"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle R_{+}^{4} \end{document} ]]></tex-math></inline-formula><italic> is positive for </italic><inline-formula><tex-math id="math-22"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle t ≥ 0 \end{document} ]]></tex-math></inline-formula><italic>.</italic></p><p><italic>Proof. </italic>The first equation of <xref ref-type="disp-formula" rid="equation-1">(1)</xref> gives</p><p><inline-formula><tex-math id="math-23"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_1(t)=k_1(0)\exp\left(\int_0^t\left[w_1\left(1-\frac{k_1}{v_1}\right)-\frac{l_1(1-\hat{m})k_4}{k_1(1-\hat{m})+j}\right]dt\right)>0. \end{document} ]]></tex-math></inline-formula></p><p>The second equation of the system <xref ref-type="disp-formula" rid="equation-1">(1)</xref> is</p><p><inline-formula><tex-math id="math-24"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_2(t)=k_2(0)\exp\left(\int_0^t\left[w_2\left(1-\frac{k_2}{v_2}\right)-\frac{l_2k_3}{k_2+j}-\frac{l_3k_4}{k_2+j}\right]dt\right)>0. \end{document} ]]></tex-math></inline-formula></p><p>From the third equation of the system <xref ref-type="disp-formula" rid="equation-1">(1)</xref>, we get</p><p><inline-formula><tex-math id="math-25"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_3(t)=k_3(0)\exp\left(\int_0^t\left[-c_1+\frac{n_1l_2k_2}{k_2+j}-\hat{h}_1\right]dt\right)>0. \end{document} ]]></tex-math></inline-formula></p><p>The last equation of system <xref ref-type="disp-formula" rid="equation-1">(1)</xref> gives</p><p><inline-formula><tex-math id="math-26"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_4(t)=k_4(0)\exp\left(\int_0^t\left[-c_2+\frac{n_2l_2(1-\hat{m})k_1}{k_1(1-\hat{m})+j}+\frac{n_3l_3k_2}{k_2+j}\right]dt\right)>0. \end{document} ]]></tex-math></inline-formula></p><p>This proves the theorem.</p><p><bold>Theorem 3.2. </bold><italic>All solutions of system </italic><xref ref-type="disp-formula" rid="equation-1">(1)</xref><italic> in </italic><inline-formula><tex-math id="math-27"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle R_{+}^{4} \end{document} ]]></tex-math></inline-formula><italic> are uniformly bounded.</italic></p><p><italic>Proof. </italic>Let us define a function as follows:</p><disp-formula id="equation-2"><tex-math id="math-28"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \begin{equation*}\begin{aligned}\bar{\omega}&=\frac{1}{\alpha}k_1+\frac{1}{\beta}k_2+\frac{1}{\gamma}k_3+\frac{1}{\delta}k_4.\end{aligned}\tag{2}\end{equation*} \end{document} ]]></tex-math></disp-formula><p>Differentiate equation <xref ref-type="disp-formula" rid="equation-1">(1)</xref> with respect to <inline-formula><tex-math id="math-29"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle ’t’ \end{document} ]]></tex-math></inline-formula>, we get</p><p><inline-formula><tex-math id="math-30"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \frac{d\bar{\omega}}{dt}=\frac{1}{\alpha}\frac{dk_1}{dt}+\frac{1}{\beta}\frac{dk_2}{dt}+\frac{1}{\gamma}\frac{dk_3}{dt}+\frac{1}{\delta}\frac{dk_4}{dt} \end{document} ]]></tex-math></inline-formula>,</p><p><inline-formula><tex-math id="math-31"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \frac{d\bar{\omega}}{dt}=\frac{1}{\alpha}\left[w_1-\frac{w_1k_1}{v_1}\right]+\frac{1}{\beta}\left[w_2-\frac{w_2k_2}{v_2}\right]-\frac{k_3}{\gamma}[c_1+\hat{h}_1]-\frac{k_4}{\delta}[c_2] \end{document} ]]></tex-math></inline-formula>.</p><p>For any <inline-formula><tex-math id="math-32"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \xi >0 \end{document} ]]></tex-math></inline-formula>.</p><p><inline-formula><tex-math id="math-33"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \frac{d\bar{\omega}}{dt}+\xi\bar{\omega}\leq\frac{v_1}{4\alpha w_1}(w_1+\xi)^2+\frac{v_2}{4\beta w_2}(w_2+\xi)^2 \end{document} ]]></tex-math></inline-formula>.</p><p>we define a constant <inline-formula><tex-math id="math-34"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle η > 0 \end{document} ]]></tex-math></inline-formula> such that <inline-formula><tex-math id="math-35"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \eta=\frac{\tilde{v}_1}{4\alpha w_1}(w_1+\xi)^2+\frac{v_2}{4\beta w_2}(w_2+\xi)^2 \end{document} ]]></tex-math></inline-formula>.  It</p><p>shows that <inline-formula><tex-math id="math-36"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \frac{d\bar{\omega}}{dt}+\xi\bar{\omega}\leq\eta \end{document} ]]></tex-math></inline-formula>. Applying theory of differential inequality, we obtain <inline-formula><tex-math id="math-37"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{\omega}(k_1(t),k_2(t),k_3(t),k_4(t))<\frac{\eta}{\xi}\left(1-e^{-\xi t}\right)+\bar{\omega}(k_1(0),k_2(0),k_3(0),k_4(0))e^{-\xi t} \end{document} ]]></tex-math></inline-formula>.</p><p>As <inline-formula><tex-math id="math-38"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle t\rightarrow\infty \end{document} ]]></tex-math></inline-formula>, this become <inline-formula><tex-math id="math-39"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle 0\leq\bar{\omega}(k_1(t),k_2(t),k_3(t),k_4(t))\leq\frac{\eta}{\xi} \end{document} ]]></tex-math></inline-formula>. Hence, that concludes all solution of <xref ref-type="disp-formula" rid="equation-1">(1)</xref> with initial condition that initiate in <inline-formula><tex-math id="math-40"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle R_{+}^{4} \end{document} ]]></tex-math></inline-formula> are bounded to the region <inline-formula><tex-math id="math-41"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \nabla=\left\{(k_1(t),k_2(t),k_3(t),k_4(t))\in R_{+}^{4}\mid\bar{\omega}=\frac{\eta}{\xi}+\epsilon\;\vee\;\epsilon\right\} \end{document} ]]></tex-math></inline-formula>.</p></sec><sec id="sec-4"><title>4.    EXISTENCE OF EQUILIBRIUM POINTS</title><p>Various equilibrium points of the system have been examined. The system is observed to have six possible equilibrium points. <inline-formula><tex-math id="math-42"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat { m }\ne1 \end{document} ]]></tex-math></inline-formula> and <inline-formula><tex-math id="math-43"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat { m }\ne1 \end{document} ]]></tex-math></inline-formula>, all the equilib-rium points satisfy the condition. These equilibrium points are now presented as follows:</p><p>(i)    Trivial equilibrium <inline-formula><tex-math id="math-44"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat { E }_1 (0, 0, 0, 0) \end{document} ]]></tex-math></inline-formula> represents the complete extinction of all prey and predator populations under extreme ecological stress.</p><p>(ii)     Coexistence of prey without predator equilibrium <inline-formula><tex-math id="math-45"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat { E }_2(v_1, v_2, 0, 0) \end{document} ]]></tex-math></inline-formula> represents the persistence of both prey species in the absence of predators.</p><p>(iii)     Single prey with dual predator coexistence equilibrium</p><p><inline-formula><tex-math id="math-46"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_3\left(\frac{c_2j}{(1-\hat{m})(n_2l_1-c_2)},0,jw_2-\frac{l_3}{l_2}\left[\frac{w_1n_2c_2j}{c_2}\right],\frac{w_1n_2c_2j}{c_2}\right) \end{document} ]]></tex-math></inline-formula>occurs when</p><p><inline-formula><tex-math id="math-47"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle n_2l_1>c_2 \end{document} ]]></tex-math></inline-formula>, <inline-formula><tex-math id="math-48"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle jw_2>\frac{l_3w_1n_2\mathcal{J}}{l_2c_2} \end{document} ]]></tex-math></inline-formula>and <inline-formula><tex-math id="math-49"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle 1>\frac{c_2j}{v_1(1-\hat{m})(n_2l_1-c_2)} \end{document} ]]></tex-math></inline-formula>ensuring that one prey species persists and sustains both predator populations while the other prey is absent.</p><p>Where <inline-formula><tex-math id="math-50"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \mathcal{J} = 1-\frac{c_2j}{v_1(1-\hat{m})(n_2l_1-c_2)} \end{document} ]]></tex-math></inline-formula></p><p>(iv)     Generalized predator absent equilibrium<inline-formula><tex-math id="math-51"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_4\left(v_1,T,\frac{w_2j}{l_1v_1}\left[v_2(T+1)-T\right],0\right) \end{document} ]]></tex-math></inline-formula></p><p>exists when <inline-formula><tex-math id="math-52"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle n_1l_2>c_1+\hat{h}_1 \end{document} ]]></tex-math></inline-formula>and<inline-formula><tex-math id="math-53"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle v_2(T+1)>T \end{document} ]]></tex-math></inline-formula>under which both prey coexist with the specialist predator while the generalist predator is absent.</p><p>(v)     Coexistence equilibrium point <inline-formula><tex-math id="math-54"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_5(k_1^*,k_2^*,k_3^*,k_4^*) \end{document} ]]></tex-math></inline-formula>exists when all population components are positive, representing the simultaneous persistence of both prey and both predator species.</p><p>The equilibrium points are presented below:</p><fig id="figure-2"><label>Figure 2.</label><caption><p>Graphical representation of the model <xref ref-type="disp-formula" rid="equation-1">(1)</xref> equilibria</p></caption><graphic xlink:href="https://jims-a.org/index.php/jimsa/article/download/2229/544/13877" mime-subtype="png" mimetype="image"><alt-text>Figure 2.</alt-text></graphic></fig><table-wrap id="table-2"><label>Table 2.</label><caption><p>Key parameters and effects on ecosystem dynamics forall equilibrium points.</p></caption><table><colgroup><col></col><col></col><col></col></colgroup><thead><tr><th scope="col">Equilibrium Point</th><th scope="col">Key  Parameters</th><th scope="col">Effect on Ecosystem Dynamics</th></tr></thead><tbody><tr><td><inline-formula><tex-math id="math-55"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_1 \end{document} ]]></tex-math></inline-formula></td><td>-</td><td>All species become extinct.Recovery is only possible if prey growth and carrying capacities are sufficient.</td></tr><tr><td><inline-formula><tex-math id="math-56"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_2 \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-57"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle v_1, v_2 \end{document} ]]></tex-math></inline-formula></td><td>Both prey populations survive in the absence of predators.</td></tr><tr><td><inline-formula><tex-math id="math-58"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_3 \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-59"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle w_1, w_2, c_2, n_2, l_1, l_2, l_3, v_1, \hat { m } \end{document} ]]></tex-math></inline-formula></td><td>One prey survives due to refuge and limited predation, while the other prey becomes extinct. Both predators per-sist with densities determined by prey growth, predator birth and death rates, and predator interactions.</td></tr><tr><td><inline-formula><tex-math id="math-60"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_4 \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-61"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle v_1, v_2, w_2, l_1, l_2, c_1, n_1, j, \hat { h_1 }, \mathcal{T} \end{document} ]]></tex-math></inline-formula></td><td>Both prey coexist with the specialist predator, while the generalist predator is absent. Population densities depend on prey growth, carrying capacities, pre-dation rates, half-saturation effects, and harvesting.</td></tr><tr><td><inline-formula><tex-math id="math-62"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_5 \end{document} ]]></tex-math></inline-formula></td><td>All model parameters</td><td>All prey and predator species coexist. Population densities are governed by prey growth, carrying capacities, predation rates, predator birth and death rates, prey refuge, half-saturation effects, and harvesting.</td></tr></tbody></table></table-wrap></sec><sec id="sec-5"><title>5.    STABILITY ANALYSIS</title><p>The dynamics behavior of the equilibrium points can be analyzed by calcu-lating the eigenvalue of the Jacobian matrix of system <xref ref-type="disp-formula" rid="equation-1">(1)</xref> given by:</p><p><inline-formula><tex-math id="math-63"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle J(k_1,k_2,k_3,k_4)=\begin{bmatrix}\gamma_{11} & 0 & 0 & \gamma_{14}\\0 & \gamma_{22} & \gamma_{23} & \gamma_{24}\\0 & \gamma_{32} & \gamma_{33} & 0\\\gamma_{41} & \gamma_{42} & 0 & \gamma_{44}\end{bmatrix}. \end{document} ]]></tex-math></inline-formula></p><p>where</p><p>,<inline-formula><tex-math id="math-64"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \begin{aligned}\gamma_{11}&=w_1-\frac{2w_1k_1}{v_1}-\frac{l_1(1-\hat{m})k_4}{k_1(1-\hat{m})+j}+\frac{l_1(1-\hat{m})k_1k_4}{\left(k_1(1-\hat{m})+j\right)^2},\\\bar{\gamma}_{12}&=0,\\\bar{\gamma}_{13}&=0,\\\bar{\gamma}_{14}&=-\frac{l_1(1-\hat{m})k_1}{k_1(1-\hat{m})+j},\\\bar{\gamma}_{21}&=0,\\\bar{\gamma}_{22}&=w_2-\frac{2w_2k_2}{v_2}-\frac{l_2k_3}{k_2+j}+\frac{l_2k_2k_3}{(k_2+j)^2}-\frac{l_3k_4}{k_2+j}+\frac{l_3k_2k_4}{(k_2+j)^2},\\\bar{\gamma}_{23}&=-\frac{l_2k_2}{k_2+j},\\\bar{\gamma}_{24}&=-\frac{l_3k_2}{k_2+j},\\\bar{\gamma}_{31}&=0,\\\bar{\gamma}_{32}&=\frac{n_1l_2k_3}{k_2+j}+\frac{n_1l_2k_2k_3}{(k_2+j)^2},\\\bar{\gamma}_{33}&=-c_1+\frac{n_1l_2k_2}{k_2+j}-\hat{h}_1,\\\bar{\gamma}_{34}&=0,\\\bar{\gamma}_{41}&=\frac{n_2l_1(1-\hat{m})k_4}{k_1(1-\hat{m})+j}-\frac{n_2l_1(1-\hat{m})k_1k_4}{\left(k_1(1-\hat{m})+j\right)^2},\\\bar{\gamma}_{42}&=\frac{n_3l_3k_4}{k_2+j}-\frac{n_3l_3k_2k_4}{(k_2+j)^2},\\\bar{\gamma}_{43}&=0,\\\bar{\gamma}_{44}&=-\hat{c}_2+\frac{\hat{n}_2\tilde{l}_1(1-\hat{m})k_1}{k_1(1-\hat{m})+j}+\frac{\hat{n}_3\tilde{l}_3k_2}{k_2+j}.\end{aligned} \end{document} ]]></tex-math></inline-formula></p><p><bold>Theorem 5.1. </bold><italic>The trivial equilibrium point </italic><inline-formula><tex-math id="math-65"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat { E }_1 (0, 0, 0, 0) \end{document} ]]></tex-math></inline-formula><italic> of model </italic><xref ref-type="disp-formula" rid="equation-1">(1)</xref><italic> is a saddle point.</italic></p><p><italic>Proof</italic>. The jacobian matrix is,</p><p><inline-formula><tex-math id="math-66"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle J(0,0,0,0)=\begin{bmatrix}\widetilde{w}_1 & 0 & 0 & 0\\0 & \widetilde{w}_2 & 0 & 0\\0 & 0 & -\widetilde{c}_1 & 0\\0 & 0 & 0 & -\widetilde{c}_2\end{bmatrix} \end{document} ]]></tex-math></inline-formula></p><p>The eigenvalues are <italic>λ</italic>1 = <italic>w</italic>1, <italic>λ</italic>2 = <italic>w</italic>2, <italic>λ</italic>3 = −<italic>c</italic>1 − <italic>h</italic>ˆ1 and <italic>λ</italic>3 = −<italic>c</italic>2<italic>. </italic></p><p>Thus, being a saddle point, it is unstable.</p><p><bold>Theorem 5.2. </bold><italic>Equilibrium point of model </italic><xref ref-type="disp-formula" rid="equation-1">(1)</xref><italic> is stable if the condition</italic></p><p><inline-formula><tex-math id="math-67"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle c_1 > \dfrac{n_1 v_1 l_2}{v_2 + j} \quad \end{document} ]]></tex-math></inline-formula><italic>and </italic><inline-formula><tex-math id="math-68"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \quad c_2 > \dfrac{n_2 l_1 (1-\hat{m}) v_1}{v_1 (1-\hat{m}) + j} + \dfrac{n_3 l_3 v_2}{v_2 + j} \quad \end{document} ]]></tex-math></inline-formula><italic>hold.</italic></p><p><italic>Proof. </italic>The jacobian matrix is,</p><p><inline-formula><tex-math id="math-69"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle J(k_1,k_2,0,0) =\begin{bmatrix}-\tilde{w}_1 & 0 & 0 & -\dfrac{l_1(1-\hat{m})v_1}{(v_1(1-\hat{m})+j)} \\[2ex]0 & -\tilde{w}_2 & -\dfrac{l_2 v_2}{v_2+j} & -\dfrac{\tilde{l}_2 \tilde{v}_2}{\tilde{v}_2+\tilde{j}} \\[2ex]0 & 0 & -c_1+\dfrac{n_1 l_3 v_2}{(v_2+j)} & 0 \\[2ex]0 & 0 & 0 & -c_2+\dfrac{n_2 l_1(1-\hat{m})v_1}{(v_1(1-\hat{m})+j)}+\dfrac{n_3 l_3 v_2}{(v_2+j)}\end{bmatrix}. \end{document} ]]></tex-math></inline-formula></p><p>The eigenvalue of  <inline-formula><tex-math id="math-70"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_2(v_1, v_2, 0, 0) \text{ are } \lambda_1 = -w_1, \ \lambda_2 = -w_2, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-71"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \lambda_3 = -c_2 + \dfrac{n_1 l_2 v_2}{(v_2+j)} \quad \text{and} \quad \lambda_4 = -c_2 + \dfrac{n_2 l_1(1-\hat{m}v_1)}{v_1(1-\hat{m})+j} + \dfrac{n_3 l_3 v_2}{(v_2+j)}. \end{document} ]]></tex-math></inline-formula></p><p>In the case where <inline-formula><tex-math id="math-72"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle c_1 > \dfrac{n_1 v_2 l_2}{v_2+j} \quad \text{and} \quad c_2 > \dfrac{n_2 l_1(1-\hat{m})v_1}{v_1(1-\hat{m})+j} + \dfrac{n_3 l_3 v_2}{v_2+j} \end{document} ]]></tex-math></inline-formula>the Equilibrium point <inline-formula><tex-math id="math-73"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_3 \end{document} ]]></tex-math></inline-formula>is stable.</p><p>Prey populations persist while predators cannot invade. This reflects a sit-uation where prey refuges and predator mortality prevent predator establishment, allowing prey to maintain a stable population.</p><p><bold>Theorem 5.3. </bold><italic>Single prey with dual predator coexistence equilibrium point </italic><inline-formula><tex-math id="math-74"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_3 \end{document} ]]></tex-math></inline-formula><italic> is stable if the condition </italic><inline-formula><tex-math id="math-75"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle tr(J(\hat{E}_3)) < 0, \quad Det(J(\hat{E}_3)) < 0, \end{document} ]]></tex-math></inline-formula><italic></italic><inline-formula><tex-math id="math-76"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle DM(J(\hat{E}_3)) tr(J(\hat{E}_3)) < Det(J(\hat{E}_3)) \end{document} ]]></tex-math></inline-formula><italic>and  </italic><inline-formula><tex-math id="math-77"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle w_2 + \dfrac{l_3 w_1 n_2 \mathfrak{I}}{l_2 c_2 j} < w_2 l_2 + \dfrac{l_3 w_1 n_2 \mathfrak{I}}{j c_2} \end{document} ]]></tex-math></inline-formula><italic>hold.</italic></p><p><italic>Proof. </italic>The jacobian matrix is,</p><p><inline-formula><tex-math id="math-78"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle J(k_1,0,k_3,k_4) =\begin{bmatrix}\chi_{11} & 0 & 0 & \chi_{14} \\[1.5ex]0 & \chi_{22} & 0 & 0 \\[1.5ex]0 & \chi_{32} & \chi_{33} & 0 \\[1.5ex]\chi_{41} & \chi_{42} & 0 & \chi_{44}\end{bmatrix}. \end{document} ]]></tex-math></inline-formula></p><p>Where</p><p><inline-formula><tex-math id="math-79"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{11} = w_1 - \dfrac{2c_2 w_1 j}{v_1(1-\hat{m})(n_2 l_1) - c_2} - \dfrac{\mathfrak{I}(1-\hat{m})w_1(n_2 l_1 - c_2)}{c_2 j} + w_1(1-\hat{m})\mathfrak{I}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-80"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{12} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-81"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{13} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-82"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{14} = -\dfrac{c_2}{n_2}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-83"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{21} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-84"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{22} = w_2 - \dfrac{l_2^2 c_2 w_2 j - l_3 w_1 n_2 \mathfrak{I}}{j c_2 l_2} - \dfrac{l_3 w_1 n_2 \mathfrak{I}}{c_2 j}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-85"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{23} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-86"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{24} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-87"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{31} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-88"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{32} = \dfrac{n_1 l_2^2 c_2 w_2 j - l_3 w_1 n_2 \mathfrak{I}}{j c_2 l_2}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-89"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{33} = -c_1 - \hat{h}_1, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-90"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{34} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-91"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{41} = \dfrac{n_2^2 l_1 w_1 (1-\hat{m})(n_2 l_1 - c_2)\mathfrak{I}}{c_2(c_2 j + (1-\hat{m})(n_2 l_1 - c_2))} - \dfrac{n_2 l_1 w_1 (1-\hat{m})(n_2 l_1 - c_2)\mathfrak{I}}{\left(j(c_2 + (1-\hat{m})(n_2 l_1 - c_2))\right)^2}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-92"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{42} = \dfrac{n_3 n_2 l_3 w_1 \mathfrak{I}}{c_2 j}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-93"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{43} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-94"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \chi_{44} = -c_2 \hat{m}. \end{document} ]]></tex-math></inline-formula></p><p>The characteristic equation is  <inline-formula><tex-math id="math-95"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle (\chi_{22} - \lambda) \left (\lambda^3 - \text{tr}(J(\hat{E}_3))\lambda^2 + \text{DM}(J(\hat{E}_3))\lambda - \text{Det}(J(\hat{E}_3))\right) = 0. \end{document} ]]></tex-math></inline-formula></p><p>Where,</p><p><inline-formula><tex-math id="math-96"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{tr}(J(\hat{E}_3)) = \chi_{11} + \chi_{22} + \chi_{33}. \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-97"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{DM}(J(\hat{E}_3)) = 3\chi_{11}\chi_{33}\chi_{44} - \chi_{14}\chi_{41}\chi_{44}. \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-98"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{Det}(J(\hat{E}_3)) = \chi_{11}\chi_{33}\chi_{44} + \chi_{14}\chi_{41}\chi_{33}. \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-99"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \lambda_1 = \tilde{w}_2 - \dfrac{\tilde{l}_2^2 \tilde{c}_2 \tilde{w}_2 \tilde{j} - \tilde{l}_3 \tilde{w}_1 \tilde{n}_2 \mathfrak{I}}{\tilde{j}\tilde{c}_2\tilde{l}_2} - \dfrac{\tilde{l}_3 \tilde{w}_1 \tilde{n}_2 \mathfrak{I}}{\tilde{c}_2 \tilde{j}}. \end{document} ]]></tex-math></inline-formula></p><p>Here, </p><p><inline-formula><tex-math id="math-100"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle J(\hat{E}_3) =\begin{bmatrix}\bar{\chi}_{11} & 0 & \bar{\chi}_{14} \\[1.5ex]0 & \bar{\chi}_{33} & 0 \\[1.5ex]\bar{\chi}_{41} & 0 & \bar{\chi}_{44}\end{bmatrix} \end{document} ]]></tex-math></inline-formula></p><p>In the case where <inline-formula><tex-math id="math-101"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{tr}(J(\hat{E}_3)) < 0, \ \text{Det}(J(\hat{E}_3)) < 0, \end{document} ]]></tex-math></inline-formula><inline-formula><tex-math id="math-102"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{DM}(J(\hat{E}_3))\,\text{tr}(J(\hat{E}_3)) < \text{Det}(J(\hat{E}_3)) \end{document} ]]></tex-math></inline-formula> and  <inline-formula><tex-math id="math-103"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \tilde{w}_2 + \dfrac{\tilde{l}_3 \tilde{w}_1 \tilde{n}_2 \mathfrak{I}}{\tilde{l}_2 \tilde{c}_2 \tilde{j}} < \tilde{w}_2 \tilde{l}_2 + \dfrac{\tilde{l}_3 \tilde{w}_1 \tilde{n}_2 \mathfrak{I}}{\tilde{j}\tilde{c}_2} \end{document} ]]></tex-math></inline-formula>is stable.</p><p>Under these conditions, the single prey species and both predators coexist stably. The inequalities ensure that predator growth is balanced by prey availability and mortality, preventing any species from overexploiting the prey. Ecologically, this reflects a stable prey predator system where interactions are regulated and no population collapses occur.</p><p><bold>Theorem 5.4. </bold><italic>Equilibrium point </italic><inline-formula><tex-math id="math-104"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_4 \end{document} ]]></tex-math></inline-formula><italic> is stable if the condition </italic><inline-formula><tex-math id="math-105"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle tr(J(\hat{E}_4)) < 0, \end{document} ]]></tex-math></inline-formula><inline-formula><tex-math id="math-106"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{Det}(J(\hat{E}_4)) < 0, \text{DM}(J(\hat{E}_4))\,\text{tr}(J(\hat{E}_4)) < \text{Det}(J(\hat{E}_4)), \end{document} ]]></tex-math></inline-formula><italic>hold.</italic></p><p><italic>Proof. </italic>The jacobian matrix is,</p><p><inline-formula><tex-math id="math-107"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle J(k_1,k_2,k_3,0) =\begin{bmatrix}\zeta_{11} & 0 & 0 & \zeta_{14} \\[1.5ex]0 & \zeta_{22} & \zeta_{23} & \zeta_{24} \\[1.5ex]0 & \zeta_{32} & \zeta_{33} & \zeta_{34} \\[1.5ex]0 & 0 & 0 & \zeta_{44}\end{bmatrix} \end{document} ]]></tex-math></inline-formula></p><p>Where</p><p><inline-formula><tex-math id="math-108"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{11} = -w_1, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-109"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{12} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-110"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{13} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-111"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{14} = -\dfrac{l_1(1-\hat{m})v_1}{(v_1(1-\hat{m})+j)}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-112"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{21} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-113"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{22} = w_2 - \dfrac{2w_2 \mathcal{T}}{v_2} - \dfrac{l_2 w_2 j[v_2(\mathcal{T}+1) - \mathcal{T}]}{l_1 v_1(\mathcal{T}+j)} + \dfrac{l_2 \mathcal{T} w_2 j (v_2(\mathcal{T}+1) - \mathcal{T})}{l_1 v_1 (\mathcal{T}+j)^2}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-114"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{23} = -\dfrac{l_2 \mathcal{T}}{(\mathcal{T}+j)}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-115"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{24} = -\dfrac{l_3 \mathcal{T}}{(\mathcal{T}+j)}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-116"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{31} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-117"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{32} = \dfrac{n_1 l_2 w_2 j (v_2(\mathcal{T}+1) - \mathcal{T})}{l_1 v_1(\mathcal{T}+j)} - \dfrac{n_1 l_2 \mathcal{T} w_2 j (v_2(\mathcal{T}+1) - \mathcal{T})}{l_1 v_1 (\mathcal{T}+j)^2}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-118"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{33} = -c_1 + \dfrac{n_1 l_2 \mathcal{T}}{(\mathcal{T}+j)} - \hat{h}_1, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-119"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{34} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-120"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{42} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-121"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{43} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-122"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \zeta_{44} = -c_2 + \dfrac{n_2 l_1(1-\hat{m})v_1}{(v_1(1-\hat{m})+j)} + \dfrac{n_3 l_3 \mathcal{T}}{\mathcal{T}+j}. \end{document} ]]></tex-math></inline-formula></p><p>The characteristic equation is</p><p><inline-formula><tex-math id="math-123"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle (\zeta_{44} - \lambda)\left(\lambda^3 - \text{tr}(J(\hat{E}_4))\lambda^4 + \text{DM}(J(\hat{E}_4))\lambda - \text{Det}(J(\hat{E}_4))\right) = 0. \end{document} ]]></tex-math></inline-formula></p><p>Where</p><p><inline-formula><tex-math id="math-124"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{tr}(J(\hat{E}_4)) = \zeta_{11} + \zeta_{22} + \zeta_{33}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-125"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{DM}(J(\hat{E}_4)) = 3\zeta_{11}\zeta_{22}\zeta_{33} - \zeta_{11}\zeta_{23}\zeta_{32}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-126"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{Det}(J(\hat{E}_4)) = \zeta_{11}\zeta_{22}\zeta_{33} - \zeta_{11}\zeta_{23}\zeta_{32} \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-127"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \lambda_1 = -c_2 + \dfrac{n_2 l_1(1-\hat{m})v_1}{(v_1(1-\hat{m})+j)} + \dfrac{n_3 l_3 \mathcal{T}}{\mathcal{T}+j}. \end{document} ]]></tex-math></inline-formula></p><p>Here</p><p><inline-formula><tex-math id="math-128"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle J(\hat{E}_4) =\begin{bmatrix}\zeta_{11} & 0 & 0 \\[1.5ex]0 & \zeta_{22} & \zeta_{23} \\[1.5ex]0 & \zeta_{23} & \zeta_{33}\end{bmatrix}. \end{document} ]]></tex-math></inline-formula></p><p>In the case where <inline-formula><tex-math id="math-129"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{tr}(J(\hat{E}_4)) < 0, \ \text{Det}(J(\hat{E}_4)) < 0, \end{document} ]]></tex-math></inline-formula> is stable. This point represents sustainable coexistence where all species persist and interactions among them prevent extreme population fluctuations.</p><p><bold>Theorem 5.5. </bold><italic>Coexistence Equilibrium point </italic><inline-formula><tex-math id="math-130"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_5 (k_1^*, k_2^*, k_3^*, k_1^*) \end{document} ]]></tex-math></inline-formula><italic> of model (1) stable if the</italic><italic>condition</italic><inline-formula><tex-math id="math-131"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{tr}(\hat{E}_5 < 0, [\text{DM of order(2)}(\hat{E}_5)][tr(\hat{E}_5)] - [\text{DM of Order(3)}(\hat{E}_5)] > 0 \end{document} ]]></tex-math></inline-formula><italic> and </italic><inline-formula><tex-math id="math-132"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \big([\text{DM of order}(3)(\hat{E}_5)]\big[(\text{tr}(\hat{E}_5))(\text{DM of order}(2)(\hat{E}_5)) \end{document} ]]></tex-math></inline-formula><inline-formula><tex-math id="math-133"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle - (\text{DM of order}(3)(\hat{E}_5))\big] - \text{Det}((\hat{E}_5))\,\text{tr}(\hat{E}_5)^2\big) > 0. \end{document} ]]></tex-math></inline-formula></p><p>Proof.</p><p><inline-formula><tex-math id="math-134"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle J(k_1,k_2,k_3,k_4) =\begin{bmatrix}V_{11} & 0 & 0 & V_{14} \\[1.5ex]0 & V_{22} & V_{23} & V_{24} \\[1.5ex]0 & V_{32} & V_{33} & 0 \\[1.5ex]V_{41} & V_{42} & 0 & V_{44}\end{bmatrix}. \end{document} ]]></tex-math></inline-formula></p><p>Where</p><p><inline-formula><tex-math id="math-135"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{11} = w_1 - \dfrac{2w_1 k_1^*}{v_1} - \dfrac{l_1(1-\hat{m})k_4^*}{(k_1^*(1-\hat{m})+j)} + \dfrac{l_1(1-\hat{m})k_1^* k_4^*}{(k_1^*(1-\hat{m})+j)^2}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-136"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{12} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-137"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{13} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-138"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{14} = -\dfrac{l_1(1-\hat{m})k_4^*}{(k_1^*(1-\hat{m})+j)}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-139"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{21} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-140"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{22} = w_2 - \dfrac{2w_2 k_2^*}{v_2} - \dfrac{l_2 k_3^*}{(k_2^*+j)} + \dfrac{l_2 k_2^* k_3^*}{(k_2^*+j)^2} - \dfrac{l_3 k_4^*}{(k_2^*+j)} + \dfrac{l_3 k_2^* k_4^*}{(k_2^*+j)^2}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-141"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{23} = -\dfrac{l_2 k_2^*}{(k_2^*+j)}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-142"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{24} = -\dfrac{l_3 k_2^*}{(k_2^*+j)}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-143"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{31} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-144"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{32} = \dfrac{n_1 l_2 k_3^*}{(k_2^*+j)} + \dfrac{n_1 l_2 k_2^* k_3^*}{(k_2^*+j)^2}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-145"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{33} = -c_1 + \dfrac{n_1 l_2 k_2^*}{(k_2^*+j)} - \hat{h}_1, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-146"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{34} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-147"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{41} = \dfrac{n_2 l_1(1-\hat{m})k_4^*}{(k_1^*(1-\hat{m})+j)} - \dfrac{n_2 l_1(1-\hat{m})k_1^* k_4^*}{(k_1^*(1-\hat{m})+j)^2}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-148"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{42} = \dfrac{n_3 l_3 k_4^*}{(k_2^*+j)} = \dfrac{n_3 l_3 k_2^* k_4^*}{(k_2^*+j)^2}, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-149"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{43} = 0, \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-150"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle V_{44} = -c_2 + \dfrac{n_2 l_1(1-\hat{m})k_1^*}{(k_1^*(1-\hat{m})+j)} + \dfrac{n_3 l_3 k_2^*}{(k_2^*+j)}. \end{document} ]]></tex-math></inline-formula></p><p>The characteristic equation is</p><p><inline-formula><tex-math id="math-151"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \lambda^4 - \text{tr}(\hat{E}_5)\lambda^3 + \text{DM of order}(2)(\hat{E}_5) - \text{DM of order}(3)(\hat{E}_5) + \text{Det}(\hat{E}_5) = 0. \end{document} ]]></tex-math></inline-formula></p><p>Where,</p><p><inline-formula><tex-math id="math-152"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{tr}(J(\hat{E}_5)) = V_{11} + V_{22} + V_{33} + V_{44}. \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-153"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{DM of order}(2)(J(\hat{E}_6)) = V_{11}(V_{22}+V_{33}+V_{44}) + V_{22}(V_{33}+V_{44}) + V_{33}V_{44} \\\hspace{4cm} - (V_{14}V_{41} + V_{24}V_{42} + V_{23}V_{32}). \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-154"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{DM of order}(3)(J(\hat{E}_5)) = 4V_{11}V_{22}V_{33}V_{44} - (V_{11}V_{33}V_{24}V_{42} + V_{11}V_{23}V_{32}V_{44}). \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-155"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{DM of order}(3)(J(\hat{E}_5)) = 4V_{11}V_{22}V_{33}V_{44} - (V_{11}V_{33}V_{24}V_{42} + V_{11}V_{23}V_{32}V_{44}). \end{document} ]]></tex-math></inline-formula></p><p><inline-formula><tex-math id="math-156"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{Det}(J(\hat{E}_5)) = V_{11}\big[2V_{22}V_{33}V_{44} - 2(V_{23}V_{32}V_{44} + V_{24}V_{33}V_{42})\big]. \end{document} ]]></tex-math></inline-formula></p><p>In the case where <inline-formula><tex-math id="math-157"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{tr}(\hat{E}_5) < 0, \ [\text{DM of order}(2)(\hat{E}_5)][\text{tr}(\hat{E}_5)] - [\text{DM of order}(3)(\hat{E}_5)] > 0 \end{document} ]]></tex-math></inline-formula></p><p>and  <inline-formula><tex-math id="math-158"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \big([\text{DM of order}(3)(\hat{E}_5)]\big[(\text{tr}(\hat{E}_5))(\text{DM of order}(2)(\hat{E}_5)) - (\text{DM of order}(3)(\hat{E}_5)) \end{document} ]]></tex-math></inline-formula><inline-formula><tex-math id="math-159"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \text{Det}((\hat{E}_5))(\text{tr}(\hat{E}_5))^2 > 0 \end{document} ]]></tex-math></inline-formula> is stable.</p><p>This equilibrium represents a fully stable coexistence of all species. Predator and prey populations are regulated by their interactions, growth and mortality (or harvesting), so no species ove exploits another. Small disturbances in populations decay over time, maintaining the balance of the ecosystem.</p><table-wrap id="table-3"><label>Table 3</label><caption><p>Stability comparison of all equilibrium points.</p></caption><table><colgroup><col></col><col></col></colgroup><thead><tr><th scope="col">Equilibrium Point</th><th scope="col">Relative Stability</th></tr></thead><tbody><tr><td><inline-formula><tex-math id="math-160"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_1 \end{document} ]]></tex-math></inline-formula></td><td>This equilibrium is the least stable because any small intro-duction of populations can move the system away from this state.</td></tr><tr><td><inline-formula><tex-math id="math-161"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_2 \end{document} ]]></tex-math></inline-formula></td><td>This equilibrium is more stable than <inline-formula><tex-math id="math-162"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_1 \end{document} ]]></tex-math></inline-formula> because</td></tr><tr><td><inline-formula><tex-math id="math-163"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_3 \end{document} ]]></tex-math></inline-formula></td><td>One prey survives due to refuge and limited predation, while the other prey becomes extinct. Both predators persist with densities shaped by prey growth, predator birth and death rates, and predator interactions.</td></tr><tr><td><inline-formula><tex-math id="math-164"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_4 \end{document} ]]></tex-math></inline-formula></td><td>This equilibrium is less stable than <italic>E</italic>ˆ3 because it involves two prey and one predator, requiring a precise balance between species interactions.</td></tr><tr><td><inline-formula><tex-math id="math-165"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{E}_5 \end{document} ]]></tex-math></inline-formula></td><td>This equilibrium has the most restrictive stability because all species coexist, requiring careful balance among growth, preda-tion, and harvesting, and small disturbances can easily desta-bilize the system.but it can be affected if predators invade.prey populations can persist without predators,</td></tr></tbody></table></table-wrap></sec><sec id="sec-6"><title>6.   NUMERICAL SIMULATION</title><p>The proposed model is not based on real ecological data or a specific case study therefore all parameter values used in the numerical simulations are purely hypothetical and chosen for illustrative purposes. The values are selected to be positive and within reasonable ranges to ensure biologically feasible solutions and to satisfy the analytical conditions derived in this section. Different sets of parameters are employed in Figures 1, 2, and 3 to illustrate distinct dynamical behaviors of the system and to demonstrate the qualitative validity of the theoretical results. All simulations are performed using MATLAB R2024b. The values are,</p><table-wrap id="table-4"><label>Table 4</label><caption><p>Parameter Values</p></caption><table><colgroup><col></col><col></col><col></col><col></col></colgroup><thead><tr><th scope="col">Parameters</th><th scope="col">Set 1</th><th scope="col">Set 2</th><th scope="col">Set 3</th></tr></thead><tbody><tr><td><inline-formula><tex-math id="math-166"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_1(0) \end{document} ]]></tex-math></inline-formula></td><td>4.56</td><td>4.56</td><td>4.56</td></tr><tr><td><inline-formula><tex-math id="math-167"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_2(0) \end{document} ]]></tex-math></inline-formula></td><td>7.91</td><td>7.91</td><td>7.91</td></tr><tr><td><inline-formula><tex-math id="math-168"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_3(0) \end{document} ]]></tex-math></inline-formula></td><td>6.23</td><td>6.23</td><td>6.23</td></tr><tr><td><inline-formula><tex-math id="math-169"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle k_4(0) \end{document} ]]></tex-math></inline-formula></td><td>2.034</td><td>2.034</td><td>2.034</td></tr><tr><td><inline-formula><tex-math id="math-170"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{w}_1 \end{document} ]]></tex-math></inline-formula></td><td>14.67</td><td>14.67</td><td>14.67</td></tr><tr><td><inline-formula><tex-math id="math-171"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{w}_2 \end{document} ]]></tex-math></inline-formula></td><td>16.75</td><td>16.75</td><td>16.75</td></tr><tr><td><inline-formula><tex-math id="math-172"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{v}_1 \end{document} ]]></tex-math></inline-formula></td><td>40</td><td>40</td><td>40</td></tr><tr><td><inline-formula><tex-math id="math-173"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{v}_2 \end{document} ]]></tex-math></inline-formula></td><td>45</td><td>45</td><td>45</td></tr><tr><td><inline-formula><tex-math id="math-174"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{l}_1 \end{document} ]]></tex-math></inline-formula></td><td>2.74</td><td>2.74</td><td>2.74</td></tr><tr><td><inline-formula><tex-math id="math-175"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{l}_2 \end{document} ]]></tex-math></inline-formula></td><td>1.91</td><td>1.91</td><td>1.91</td></tr><tr><td><inline-formula><tex-math id="math-176"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{l}_3 \end{document} ]]></tex-math></inline-formula></td><td>1.05</td><td>1.05</td><td>1.05</td></tr><tr><td><inline-formula><tex-math id="math-177"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{n}_1 \end{document} ]]></tex-math></inline-formula></td><td>1.51</td><td>1.51</td><td>1.51</td></tr><tr><td><inline-formula><tex-math id="math-178"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{n}_2 \end{document} ]]></tex-math></inline-formula></td><td>1.95</td><td>1.95</td><td>1.95</td></tr><tr><td><inline-formula><tex-math id="math-179"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{n}_3 \end{document} ]]></tex-math></inline-formula></td><td>1.33</td><td>1.33</td><td>1.33</td></tr><tr><td><inline-formula><tex-math id="math-180"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{j} \end{document} ]]></tex-math></inline-formula></td><td>2.82</td><td>2.82</td><td>2.82</td></tr><tr><td><inline-formula><tex-math id="math-181"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{c}_1 \end{document} ]]></tex-math></inline-formula></td><td>1.167</td><td>1.167</td><td>1.167</td></tr><tr><td><inline-formula><tex-math id="math-182"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar{c}_2 \end{document} ]]></tex-math></inline-formula></td><td>1.321</td><td>1.321</td><td>1.321</td></tr><tr><td><inline-formula><tex-math id="math-183"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{h}_1 \end{document} ]]></tex-math></inline-formula></td><td>0.989</td><td>10.56</td><td>-</td></tr><tr><td><inline-formula><tex-math id="math-184"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \hat{m} \end{document} ]]></tex-math></inline-formula></td><td>0.47</td><td>0.47</td><td>0.47</td></tr></tbody></table></table-wrap><p>Set 1 represents the case where the harvesting rate is less than the specialist predator population. Set 2 denotes values where the harvesting rate is higher than the population. Set 3 indicates no harvesting occurs in the specialist predator popuatin.</p><fig id="figure-3"><label>Figure 3.</label><caption><p>Specialist predator population&gt;harvestig rate</p></caption><graphic xlink:href="https://jims-a.org/index.php/jimsa/article/download/2229/544/13878" mime-subtype="png" mimetype="image"><alt-text>Figure 3.</alt-text></graphic></fig><fig id="figure-4"><label>Figure 4.</label><caption><p>Specialist predator population &lt; harvesting</p></caption><graphic xlink:href="https://jims-a.org/index.php/jimsa/article/download/2229/544/13879" mime-subtype="jpeg" mimetype="image"><alt-text>Figure 4.</alt-text></graphic></fig><fig id="figure-5"><label>Figure 5.</label><caption><p>Without harvesting rate</p></caption><graphic xlink:href="https://jims-a.org/index.php/jimsa/article/download/2229/544/13880" mime-subtype="jpeg" mimetype="image"><alt-text>Figure 5.</alt-text></graphic></fig></sec><sec id="sec-7"><title>7. Conclusion</title><p>This study analyzes a mathematical model with two prey species and two distinct predator types, in which the first prey species <italic>k</italic>1 is protected by a refuge. The dynamics of the specialist predator are influenced by a non constant harvest-ing strategy. Figure 1 shows the interaction structure, while Figure 2 presents the equilibrium points of the system. When the harvesting rate is lower than the specialist predator population, the predator population increases even as the prey <italic>k</italic>2 declines (Figure 3). Conversely, a higher harvesting rate reduces predator den-sity (Figure 4). In the absence of harvesting, the specialist predator population rises while the prey population decreases (Figure 5). Non constant harvesting allows the rate to vary with population density. Simulation results align with stability theory, as population trajectories approach the predicted equilibrium points and confirming their local stability. This adaptive harvesting reduces pressure at low population levels and facilitates recovery. However, the model assumes fixed parameter values and does not consider spatial heterogeneity, which may limit its applicability. Fu-ture research could extend the model by incorporating empirical data and spatial dynamics with fear effects and anti predator behavior to enhance ecological realism and predictive power.</p></sec></body><back><sec sec-type="data-availability"><title>Data Availability Statement</title><p>No data were used in this study. The results presented are based solely on mathematical assumptions and theoretical analysis of the proposed model.</p></sec><sec><title>Declarations.</title><p>The authors declare no conflict of interest.</p></sec><sec sec-type="author-contributions"><title>Author Contributions.</title><p>The author solely conceived the study, performed the mathematical analysis, and wrote the manuscript.</p></sec><ack><title>Acknowledgment.</title><p>The authors would like to thank all those who contributed indirectly to this work.</p></ack><ref-list><title>References</title><ref id="BIBR-1"><element-citation publication-type="journal"><article-title>Mathematical analysis of predator-prey model with two preys and one predator</article-title><source>International Journal of Engineering and Applied Sciences</source><volume>5</volume><issue>11</issue><person-group 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