<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE article PUBLIC "-//NLM//DTD JATS (Z39.96) Journal Publishing DTD v1.3 20210610//EN" "https://jats.nlm.nih.gov/publishing/1.3/JATS-journalpublishing1-3.dtd"><article xml:lang="en" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:ali="http://www.niso.org/schemas/ali/1.0/" dtd-version="1.3" article-type="research-article"><front><journal-meta><journal-id journal-id-type="issn">2460-0245</journal-id><journal-title-group><journal-title>Journal of the Indonesian Mathematical Society</journal-title><abbrev-journal-title>JIMS</abbrev-journal-title></journal-title-group><issn pub-type="epub">2460-0245</issn><issn pub-type="ppub">2086-8952</issn><publisher><publisher-name>IndoMS</publisher-name><publisher-loc>Indonesia</publisher-loc></publisher></journal-meta><article-meta><article-id pub-id-type="doi">10.22342/jims.v32i3.1813</article-id><article-categories><subj-group><subject>Mathematics Subject Classification</subject></subj-group></article-categories><title-group><article-title>A New Slope Averaging Technique in Heun's Method: Combining Harmonic and Root Mean Square Means</article-title><subtitle>Teknik Perata-rataan Kemiringan Baru pada Metode Heun: Menggabungkan Rata-rata Harmonik dan *Root Mean Square*</subtitle></title-group><contrib-group><contrib contrib-type="author"><contrib-id contrib-id-type="orcid">https://orcid.org/0000-0001-6896-4699</contrib-id><name><surname>Syamsudhuha</surname><given-names>Syamsudhuha</given-names></name><address><country country="ID">Indonesia</country><email>syamsudhuha@unri.ac.id</email></address><xref ref-type="aff" rid="AFF-1"></xref><xref ref-type="corresp" rid="cor-0"></xref></contrib><contrib contrib-type="author"><contrib-id contrib-id-type="orcid">https://orcid.org/0009-0002-2836-3316</contrib-id><name><surname>Imran</surname><given-names>M.</given-names></name><address><country country="ID">Indonesia</country><email>mimran@unri.ac.id</email></address><xref ref-type="aff" rid="AFF-1"></xref></contrib><contrib contrib-type="author"><contrib-id contrib-id-type="orcid">https://orcid.org/0009-0004-7428-1578</contrib-id><name><surname>Putri</surname><given-names>Ayunda</given-names></name><address><country country="ID">Indonesia</country><email>ayundaputri@lecturer.unri.ac.id</email></address><xref ref-type="aff" rid="AFF-1"></xref></contrib><contrib contrib-type="author"><contrib-id contrib-id-type="orcid">https://orcid.org/0009-0005-2718-7295</contrib-id><name><surname>Marjulisa</surname><given-names>Rike</given-names></name><address><country country="ID">Indonesia</country><email>rikemarjulisa@lecturer.unri.ac.id</email></address><xref ref-type="aff" rid="AFF-1"></xref></contrib></contrib-group><contrib-group><contrib contrib-type="editor"><name><surname>Nurwigantara</surname><given-names>Mu'amar Musa</given-names></name><address><country country="ID">Indonesia</country><email>muamar.musa.n@mail.ugm.ac.id</email></address></contrib></contrib-group><aff id="AFF-1"><institution content-type="dept">Department of Mathematics</institution><institution-wrap><institution>Riau University</institution><institution-id institution-id-type="ror">https://ror.org/00nk7p507</institution-id></institution-wrap><country country="ID">Indonesia</country></aff><author-notes><fn fn-type="coi-statement"><label>Declarations.</label><p>The authors declare no conflict of interest.</p></fn><corresp id="cor-0">Corresponding author: Syamsudhuha Syamsudhuha. Email: <email>syamsudhuha@unri.ac.id</email></corresp></author-notes><pub-date date-type="pub" iso-8601-date="2026-09-01" publication-format="electronic"><day>01</day><month>09</month><year>2026</year></pub-date><pub-date date-type="collection" iso-8601-date="2026-09-01" publication-format="electronic"><day>01</day><month>09</month><year>2026</year></pub-date><volume>32</volume><issue>3</issue><issue-title>SEPTEMBER</issue-title><fpage>1</fpage><lpage>12</lpage><elocation-id>34A12, 35E15.</elocation-id><history><date date-type="received" iso-8601-date="2024-09-22"><day>22</day><month>09</month><year>2024</year></date><date date-type="accepted" iso-8601-date="2026-02-01"><day>01</day><month>02</month><year>2026</year></date></history><permissions><copyright-statement>Copyright (c) 2026 Journal of the Indonesian Mathematical Society</copyright-statement><copyright-year>2026</copyright-year><copyright-holder>Journal of the Indonesian Mathematical Society</copyright-holder><license xlink:href="https://creativecommons.org/licenses/by-nc-nd/4.0/"><ali:license_ref xmlns:ali="http://www.niso.org/schemas/ali/1.0/">https://creativecommons.org/licenses/by-nc-nd/4.0/</ali:license_ref><license-p>This work is licensed under a Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License.</license-p></license></permissions><self-uri xlink:href="https://jims-a.org/index.php/jimsa/article/view/1813" xlink:title="1813"></self-uri><abstract><p>This paper introduces a modified version of Heun's method for solving initial value problems (IVPs) in ordinary differential equations (ODEs). The proposed method replaces the standard arithmetic mean used for the average slope in Heun's method with a novel combination of harmonic mean and root mean square (RMS) for the slopes of the tangent lines. This alteration is designed to enhance the accuracy and performance of the method. Through theoretical analysis, we establish that the modified method retains stability and consistency properties, crucial for reliable numerical solutions. Extensive numerical experiments demonstrate that the method performs well across a range of step sizes, showing notable improvements in accuracy for both small and large step sizes when compared to the standard Heun's method. These results suggest that the new approach offers a robust alternative for solving IVPs, particularly in scenarios where adaptive step sizing or high precision is required.</p></abstract><kwd-group><kwd>initial value problems</kwd><kwd>Heun's method</kwd><kwd>Euler's method</kwd><kwd>harmonic mean</kwd><kwd>root mean square</kwd></kwd-group><funding-group><funding-statement>This research received the financial support provided by the Institute for Research and Community Service (LPPM), Universitas Riau.</funding-statement></funding-group><custom-meta-group><custom-meta><meta-name>File created by JATS Editor</meta-name><meta-value>https://jatseditor.com</meta-value></custom-meta><custom-meta><meta-name>issue-created-year</meta-name><meta-value>2026</meta-value></custom-meta></custom-meta-group></article-meta></front><body><sec id="sec-1"><title>1. INTRODUCTION</title><p>Numerical solutions to initial value problems (IVPs),</p><disp-formula id="equation-1"><tex-math id="math-1"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \begin{array}{c} \frac {d y}{d t} = \xi (t, y), \\ y (0) = y _ {0}, \end{array}\tag{1} \end{document} ]]></tex-math></disp-formula><p>play a critical role in scientific and engineering applications, as exact analytical solutions are often unattainable <xref ref-type="bibr" rid="BIBR-1">[1]</xref>. These problems typically involve solving differential equations that model various real-world systems, ranging from fluid dynamics to population growth models. Over the years, a variety of classical methods have been developed to provide approximate solutions to IVPs, including the Euler method, Heun’s method, and the widely-used Runge-Kutta family of methods. Each of these approaches aims to generate numerical solutions by approximating the integral of the function over small time intervals, relying on diferent strategies for calculating the slope of the function.</p><p>The Euler method, one of the simplest techniques, estimates the solution using the slope at the initial point. While it provides a straightforward approximation, its first-order accuracy often results in significant errors for stif or complex problems <xref ref-type="bibr" rid="BIBR-2">[2]</xref>. Heun’s method, sometimes referred to as the improved Euler method, ofers a refinement by averaging the slope at the beginning and the end of the interval, thereby increasing the order of accuracy of two. Runge-Kutta methods, on the other hand, provide a general framework that further improves the accuracy and stability by computing intermediate slopes within the interval. These classical methods form the foundation for many numerical solvers in use today.</p><p>Despite their widespread use, these traditional methods such as Euler’s method, Heun’s method, and Runge-Kutta method, are not without their limitations, and over time, mathematicians have proposed modifications to enhance their accuracy, stability, and eficiency. For instance, adaptive step-size control, higher-order methods, combining transcendental functions on finite diference, and enhanced stability conditions have been incorporated into existing techniques to handle more complex or stif diferential equations as can be studied in [<xref ref-type="bibr" rid="BIBR-3">3</xref>, <xref ref-type="bibr" rid="BIBR-4">4</xref>, <xref ref-type="bibr" rid="BIBR-5">5</xref>, <xref ref-type="bibr" rid="BIBR-6">6</xref>, <xref ref-type="bibr" rid="BIBR-7">7</xref>, <xref ref-type="bibr" rid="BIBR-8">8</xref>, <xref ref-type="bibr" rid="BIBR-9">9</xref>, <xref ref-type="bibr" rid="BIBR-1">1</xref>]. These improvements have proven particularly useful for problems where the classical methods exhibit poor convergence or sufer from excessive computational cost.</p><p>In this paper, we propose a novel modification to Heun’s method by altering how the average slope of the tangents is computed. Instead of using the arithmetic mean, we replace it with the mean of harmonic mean and the root mean. The harmonic mean, which emphasizes smaller values <xref ref-type="bibr" rid="BIBR-10">[10]</xref>, and the root mean square, which provides a balanced approach between the arithmetic and geometric means <xref ref-type="bibr" rid="BIBR-11">[11]</xref>, both ofer potential improvements in accuracy and stability for specific classes of problems.</p><p>The motivation for choosing this combination arises from the nature of stif initial value problems in diferential equations, where maintaining numerical stability while controlling local truncation error is crucial. As known, the harmonic mean emphasize the smaller of two values, which suggests it may reduce the efect of large tangent slopes and hence enhance numerical stability of stif problems. Similarly, the root mean square gives more weight to larger values of slope magnitude, which suggests a potential for better approximation in regions of rapid variation. Motivated by these complementary properties, we propose combining them and develop a new method for solving initial value problems, in particular stif problem as the model.</p><p>The rest of the paper is structured as follows. In Section 2, we provide the derivation of our proposed method, the stability and consistency analysis. Section 3 we present a series of numerical experiments comparing the performance of the modified methods against traditional approaches. Finally, Section 4 ofers a conclusion and discusses potential future directions for research, including further refinements and possible applications in more complex diferential equation models.</p></sec><sec id="sec-2"><title>2. MAIN RESULTS</title><sec id="sec-3"><title>2.1. Modified Heun’s Method.</title><p>There are several methods to solve IVPs, such as Euler’s method (EuM) <xref ref-type="bibr" rid="BIBR-12">[12]</xref>, which is defined by</p><disp-formula id="equation-2"><tex-math id="math-2"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y _ {n + 1} ^ {E} = y _ {n} + h \xi (t _ {n}, y _ {n})\tag{2} \end{document} ]]></tex-math></disp-formula><p>for <inline-formula><tex-math id="math-3"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle n = 0 , 1 , 2 , \ldots \end{document} ]]></tex-math></inline-formula> . Heun’s method (HeM) <xref ref-type="bibr" rid="BIBR-12">[12]</xref> is called a predictor-corrector method where it uses Euler’s method as the predictor and the corrector is the average of the slope. This method is defined as</p><disp-formula id="equation-3"><tex-math id="math-4"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y _ {n + 1} = y _ {n} + \frac {h}{2} \left(\xi (t _ {n}, y _ {n}) + \xi (t _ {n + 1}, y _ {n + 1} ^ {E}))\right)\tag{3} \end{document} ]]></tex-math></disp-formula><p>where <inline-formula><tex-math id="math-5"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y _ { n + 1 } ^ { E } \end{document} ]]></tex-math></inline-formula> is given by <xref ref-type="disp-formula" rid="equation-2">(2)</xref>. In <xref ref-type="bibr" rid="BIBR-13">[13]</xref>, modification to Heun’s method is done by changing the average slope with harmonic mean. This method is referred to as HM and is given by the following equation:</p><disp-formula id="equation-4"><tex-math id="math-6"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y _ {n + 1} = y _ {n} + h \left(\frac {J _ {1} ^ {2} + J _ {2} ^ {2}}{J _ {1} + J _ {2}}\right)\tag{4} \end{document} ]]></tex-math></disp-formula><p>where <inline-formula><tex-math id="math-7"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle J _ { 1 } = \xi ( t _ { n } , y _ { n } ) \end{document} ]]></tex-math></inline-formula> and <inline-formula><tex-math id="math-8"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle J _ { 2 } ~ = ~ \xi ( t _ { n + 1 } , y _ { n + 1 } ^ { E } ) \end{document} ]]></tex-math></inline-formula> . Another modification to Heun’s method with the same manner is given in <xref ref-type="bibr" rid="BIBR-6">[6]</xref> where it incorporates arithmetic mean and second-order harmonic mean as the the average of the slope of the tangent of <xref ref-type="disp-formula" rid="equation-1">(1)</xref>. This method is given by</p><disp-formula id="equation-5"><tex-math id="math-9"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y _ {n + 1} = y _ {n} + \frac {h}{2} \left(\frac {J _ {1} + J _ {2}}{2} + \frac {J _ {1} ^ {2} + J _ {2} ^ {2}}{J _ {1} + J _ {2}}\right)\tag{5} \end{document} ]]></tex-math></disp-formula><p>and is called AHM.</p><p>The proposed method is developed by assuming that the average of the slope of the tangent in <xref ref-type="disp-formula" rid="equation-3">(3)</xref> is a combination of the harmonic mean and the root mean square.</p><disp-formula id="equation-6"><tex-math id="math-10"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y _ {n + 1} = y _ {n} + \frac {h}{2} \left(\frac {2 J _ {1} J _ {2}}{J _ {1} + J _ {2}} + \frac {\sqrt {2 J _ {1} ^ {2} + 2 J _ {2} ^ {2}}}{2}\right).\tag{6} \end{document} ]]></tex-math></disp-formula><p>This combination is motivated by the complementary properties of the two means. The harmonic mean gives greater weight to smaller slopes, which helps enhance numerical stability, especially for stif problems, while the root mean square emphasizes larger slopes, improving accuracy in rapidly changing regions. By combining the two means, the proposed method aims to balance stability and accuracy, making it suitable for stif and oscillatory initial value problems. This method will be identified as HRM for the rest of this study.</p></sec><sec id="sec-4"><title>2.2. Stability Analysis.</title><p>Examining the stability of solution given by a numerical method is for a general problem given by <xref ref-type="disp-formula" rid="equation-1">(1)</xref> is too complicated. Instead, we apply a model problem given in <xref ref-type="bibr" rid="BIBR-12">[12]</xref>, that is defined as follows:</p><disp-formula id="equation-7"><tex-math id="math-11"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \frac {d y}{d t} = \lambda y, \quad y (t _ {0}) = 1,\tag{7} \end{document} ]]></tex-math></disp-formula><p>and assume that <inline-formula><tex-math id="math-12"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \lambda < 0 \end{document} ]]></tex-math></inline-formula> or λ has negative real part if <inline-formula><tex-math id="math-13"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \lambda \in \mathbb { C } , \mathbb { C } \end{document} ]]></tex-math></inline-formula> is the set of complex numbers. The stability of the iterative method is achieved if the method is applied to <xref ref-type="disp-formula" rid="equation-7">(7)</xref>, the numerical solution satisfies <inline-formula><tex-math id="math-14"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y _ {h} (t _ {n}) \longrightarrow 0, \mathrm{when} t _ {n} \longrightarrow \infty , \end{document} ]]></tex-math></inline-formula> for any stepsize <inline-formula><tex-math id="math-15"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle h > 0 \end{document} ]]></tex-math></inline-formula> and <inline-formula><tex-math id="math-16"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle n = 0 , 1 , 2 , \ldots \end{document} ]]></tex-math></inline-formula></p><p>Suppose</p><disp-formula id="equation-8"><tex-math id="math-17"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \frac {d y}{d t} = \xi (t _ {n}, y _ {n}) = \lambda y _ {n}.\tag{8} \end{document} ]]></tex-math></disp-formula><p>By applying <xref ref-type="disp-formula" rid="equation-6">(6)</xref> to <xref ref-type="disp-formula" rid="equation-8">(8)</xref>, we have</p><disp-formula id="equation-9"><tex-math id="math-18"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \begin{array}{l} y _ {n + 1} = y _ {n} + \frac {h}{2} \left(\frac {2 \xi (t _ {n} , y _ {n}) \xi (t _ {n + 1} , y _ {n + 1} ^ {E})}{\xi (t _ {n} , y _ {n}) + \xi (t _ {n + 1} , y _ {n + 1} ^ {E})} + \frac {\sqrt {2 \xi (t _ {n} , y _ {n}) ^ {2} + 2 \xi (t _ {n + 1} , y _ {n + 1} ^ {E}) ^ {2}}}{2}\right) \\ = y _ {n} + \frac {h}{2} \left(\frac {2 \lambda y _ {n} \lambda y _ {n + 1} ^ {E}}{\lambda y _ {n} + \lambda y _ {n + 1} ^ {E}} + \frac {\sqrt {2 (\lambda y _ {n}) ^ {2} + 2 (\lambda y _ {n + 1} ^ {E}) ^ {2}}}{2}\right) \\ = y _ {n} + \frac {h}{2} \left(\frac {2 \lambda y _ {n} \lambda (y _ {n} + h \lambda y _ {n})}{\lambda y _ {n} + \lambda (y _ {n} + h \lambda y _ {n}))} + \frac {\sqrt {2 (\lambda y _ {n}) ^ {2} + 2 (\lambda (y _ {n} + h \lambda y _ {n})}}{2}\right). \end{array}\tag{9} \end{document} ]]></tex-math></disp-formula><p>Expanding and simplifying <xref ref-type="disp-formula" rid="equation-9">(9)</xref>, we obtain</p><disp-formula id="equation-10"><tex-math id="math-19"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y _ {n + 1} = \left(\frac {4 (\lambda h) ^ {2} + 8 \lambda h + 8 + \sqrt {2} (\lambda h) ^ {2} \sqrt {(\lambda h) ^ {2} + 2 \lambda h + 2} + 2 \sqrt {2} \lambda h \sqrt {(\lambda h) ^ {2} + 2 \lambda h + 2}}{4 \lambda h + 8}\right) y _ {n}.\tag{10} \end{document} ]]></tex-math></disp-formula><p>By running the iteration for <inline-formula><tex-math id="math-20"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle n \longrightarrow \infty , \end{document} ]]></tex-math></inline-formula> , assuming <inline-formula><tex-math id="math-21"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle z = \lambda h \end{document} ]]></tex-math></inline-formula> , and the fact that <inline-formula><tex-math id="math-22"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y ( 0 ) = 1 \end{document} ]]></tex-math></inline-formula> 1 we have</p><disp-formula id="equation-11"><tex-math id="math-23"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y _ {n + 1} = \left(\frac {4 z ^ {2} + 8 z + 8 + (\sqrt {2} z ^ {2} + 2 \sqrt {2} z) \sqrt {z ^ {2} + 2 z + 2}}{4 z + 8}\right) ^ {n}. \end{document} ]]></tex-math></disp-formula><p>Suppose <inline-formula><tex-math id="math-24"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle G ( z ) = { \frac { 4 z ^ { 2 } + 8 z + 8 + \left( { \sqrt { 2 } } z ^ { 2 } + 2 { \sqrt { 2 } } z \right) { \sqrt { z ^ { 2 } + 2 z + 2 } } } { 4 z + 8 } } \end{document} ]]></tex-math></inline-formula> , then the stability of HRM method is achieved when</p><disp-formula id="equation-12"><tex-math id="math-25"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle | G (z) | \leq 1.\tag{11} \end{document} ]]></tex-math></disp-formula><p>The stability region from <xref ref-type="disp-formula" rid="equation-12">(11)</xref> is represented by the shaded-less region in <xref ref-type="fig" rid="figure-1">Figure 1</xref> below.</p><fig id="figure-1"><label>Figure 1</label><caption><p>Stability region of HRM method</p></caption><graphic xlink:href="https://jims-a.org/index.php/jimsa/article/download/1813/575/14275" mime-subtype="jpeg" mimetype="image"><alt-text>Figure 1</alt-text></graphic></fig></sec><sec id="sec-5"><title>2.3. Consistency Analysis.</title><p>According to <xref ref-type="bibr" rid="BIBR-14">[14]</xref>, consistency of a numerical algorithm for solving IVPs is satisfied if it converges to the diferential equation for all step-size <inline-formula><tex-math id="math-26"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle h \longrightarrow 0 \end{document} ]]></tex-math></inline-formula> . Specifically, suppose IVP in <xref ref-type="disp-formula" rid="equation-1">(1)</xref> is approached with a numerical method described as</p><disp-formula id="equation-13"><tex-math id="math-27"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y _ {n + 1} = y _ {n} + h \phi (t _ {n}, y _ {n}, h),\tag{12} \end{document} ]]></tex-math></disp-formula><p>then consistency of the method is attained if</p><disp-formula id="equation-14"><tex-math id="math-28"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \lim _ {h \longrightarrow 0} \phi (t _ {n}, y _ {n}, h) = \xi (t _ {n}, y _ {n}). \end{document} ]]></tex-math></disp-formula><p>Hence, in our case, from equating <xref ref-type="disp-formula" rid="equation-6">(6)</xref> with <xref ref-type="disp-formula" rid="equation-13">(12)</xref>, we obtain</p><disp-formula id="equation-15"><tex-math id="math-29"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \phi (t _ {n}, y _ {n}, h) = \frac {1}{2} \left(\frac {2 \xi (t _ {n} , y _ {n}) \xi (t _ {n + 1} , y _ {n + 1} ^ {E})}{\xi (t _ {n} , y _ {n}) + \xi (t _ {n + 1} , y _ {n + 1} ^ {E})} + \frac {\sqrt {2 \xi (t _ {n} , y _ {n}) ^ {2} + 2 \xi (t _ {n + 1} , y _ {n + 1} ^ {E}) ^ {2}}}{2}\right).\tag{13} \end{document} ]]></tex-math></disp-formula><p><inline-formula><tex-math id="math-30"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \mathrm { B y } \end{document} ]]></tex-math></inline-formula> means of Taylor expansion, assuming that <inline-formula><tex-math id="math-31"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \xi ( t _ { n } , y _ { n } ) = \xi \end{document} ]]></tex-math></inline-formula> , and applying <xref ref-type="disp-formula" rid="equation-2">(2)</xref> we have</p><disp-formula id="equation-16"><tex-math id="math-32"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \xi (t _ {n + 1}, y _ {n + 1} ^ {E}) = \xi + \xi_ {t} h + \xi_ {y} \xi h + \frac {1}{2} \xi_ {y y} \xi^ {2} h ^ {2} + \frac {1}{2} \xi_ {t t} h ^ {2} + \xi_ {t y} h ^ {2} \xi + O (h ^ {3}),\tag{14} \end{document} ]]></tex-math></disp-formula><p>where <inline-formula><tex-math id="math-33"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \xi _ { t } = \frac { \partial \xi } { \partial t } , \xi _ { y } = \frac { \partial ^ { 2 } \xi } { \partial y } , \xi _ { y y } = \frac { \partial ^ { 2 } \xi } { \partial y \partial y } . \end{document} ]]></tex-math></inline-formula> , and <inline-formula><tex-math id="math-34"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \xi _ { t t } = \frac { \partial ^ { 2 } \xi } { \partial t \partial t } . \end{document} ]]></tex-math></inline-formula></p><p>Substituting <xref ref-type="disp-formula" rid="equation-16">(14)</xref> into <xref ref-type="disp-formula" rid="equation-15">(13)</xref> and simplifying, we have</p><disp-formula id="equation-17"><tex-math id="math-35"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \begin{array}{l} \phi (t _ {n}, y _ {n}, h) = \frac {1}{2} \left(\xi + \left(\frac {\xi_ {x}}{2} + \frac {\xi_ {y} \xi}{2}\right) h + \left(- \frac {\xi_ {y} ^ {2} \xi}{4} - \frac {\xi_ {t} ^ {2}}{4 \xi} + \frac {\xi_ {t t}}{4} + \frac {\xi_ {y y} \xi^ {2}}{4} - \frac {\xi_ {y} \xi_ {t}}{2} + \frac {\xi_ {t y} \xi}{2}\right) h ^ {2} \right. \\ \left. + \frac {\sqrt {1 6 \xi^ {2} + 1 6 \xi_ {y} \xi^ {2} h + 1 6 \xi \xi_ {t} h + 8 \xi_ {y y} \xi^ {3} h ^ {2} + 8 \xi_ {y} ^ {2} \xi^ {2} h ^ {2} + 1 6 \xi_ {t y} \xi^ {2} h ^ {2} + 1 6 \xi_ {t} \xi_ {y} \xi h ^ {2} + 8 \xi \xi_ {t t} h ^ {2} + 8 \xi_ {t} ^ {2} h ^ {2}}}{4}\right) \\ + O (h ^ {3}). \end{array} \tag {15} \end{document} ]]></tex-math></disp-formula><p>Taking the limit of <xref ref-type="disp-formula" rid="equation-17">(15)</xref> resulting in <inline-formula><tex-math id="math-36"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \lim _ {h \longrightarrow 0} \phi (t _ {n}, y _ {n}, h) = \xi , \end{document} ]]></tex-math></inline-formula> which shows that our proposed method is consistent.</p></sec></sec><sec id="sec-6"><title>3. NUMERICAL RESULTS</title><p>In this section, we test our proposed method to solve three IVPs with diferent step-size <inline-formula><tex-math id="math-37"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle h . \end{document} ]]></tex-math></inline-formula> In order to see the performance of the method, we compare its results with several numerical methods, i.e. EuM, HeM, HM, and AHM.</p><p><bold>Example 3.1</bold>. Consider the IVP</p><disp-formula id="equation-18"><tex-math id="math-38"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \begin{array}{c} \frac {d y}{d t} = \frac {1}{y (t)} \\ y (0) = 1. \end{array}\tag{16} \end{document} ]]></tex-math></disp-formula><p>The exact solution is <inline-formula><tex-math id="math-39"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y ( t ) = \sqrt { 2 t + 1 } , 0 \leq t \leq 1 \end{document} ]]></tex-math></inline-formula> . The solution is given in the following tables.</p><table-wrap id="table-1"><label>Table 1</label><caption><p>Error comparison of EuM, HeM, HM, AHM, and HRM for IVP <xref ref-type="disp-formula" rid="equation-18">(16)</xref> with h = 0.1</p></caption><table><colgroup><col></col><col></col><col></col><col></col><col></col><col></col></colgroup><thead><tr><th scope="col">t</th><th scope="col">EuM</th><th scope="col">HeM</th><th scope="col">HM</th><th scope="col">AHM</th><th scope="col">HRM</th></tr></thead><tbody><tr><td>0.100</td><td>5.346522e-03</td><td>1.534781e-04</td><td>1.534781e-04</td><td>2.903478e-03</td><td>1.457435e-03</td></tr><tr><td>0.200</td><td>7.961484e-03</td><td>3.035877e-04</td><td>7.297711e-03</td><td>4.342679e-03</td><td>1.974052e-03</td></tr><tr><td>0.300</td><td>9.858246e-03</td><td>4.478703e-04</td><td>2.249504e-02</td><td>5.573349e-03</td><td>2.385002e-03</td></tr><tr><td>0.400</td><td>1.192778e-02</td><td>5.816589e-04</td><td>4.699446e-02</td><td>6.806972e-03</td><td>2.813163e-03</td></tr><tr><td>0.500</td><td>1.436895e-02</td><td>6.970676e-04</td><td>8.294958e-02</td><td>8.138060e-03</td><td>3.319746e-03</td></tr><tr><td>0.600</td><td>1.734100e-02</td><td>7.815183e-04</td><td>1.331632e-01</td><td>9.634144e-03</td><td>3.958304e-03</td></tr><tr><td>0.700</td><td>2.102439e-02</td><td>8.155925e-04</td><td>2.012491e-01</td><td>1.135848e-02</td><td>4.790266e-03</td></tr><tr><td>0.800</td><td>2.564585e-02</td><td>7.698856e-04</td><td>2.918645e-01</td><td>1.337946e-02</td><td>5.894602e-03</td></tr><tr><td>0.900</td><td>3.150123e-02</td><td>6.004090e-04</td><td>4.110245e-01</td><td>1.577656e-02</td><td>7.377777e-03</td></tr><tr><td>1.000</td><td>3.898340e-02</td><td>2.418500e-04</td><td>5.665221e-01</td><td>1.864557e-02</td><td>9.386511e-03</td></tr></tbody></table></table-wrap><table-wrap id="table-2"><label>Table 2</label><caption><p>Error comparison of EuM, HeM, HM, AHM, and HRM for IVP <xref ref-type="disp-formula" rid="equation-18">(16)</xref> with h = 0</p></caption><table><colgroup><col></col><col></col><col></col><col></col><col></col><col></col></colgroup><thead><tr><th scope="col">t</th><th scope="col">EuM</th><th scope="col">HeM</th><th scope="col">HM</th><th scope="col">AHM</th><th scope="col">HRM</th></tr></thead><tbody><tr><td>0.010</td><td>4.950600e-05</td><td>1.000000e-09</td><td>4.975123e-03</td><td>1.240000e-07</td><td>6.100000e-08</td></tr><tr><td>0.020</td><td>4.800600e-05</td><td>2.000000e-09</td><td>9.877555e-03</td><td>2.410000e-07</td><td>1.180000e-07</td></tr><tr><td>.030</td><td>4.657900e-05</td><td>3.000000e-09</td><td>1.470973e-02</td><td>3.520000e-07</td><td>1.710000e-07</td></tr><tr><td><inline-formula><tex-math id="math-40"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-41"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-42"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-43"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-44"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-45"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>0.360</td><td>2.144700e-05</td><td>1.200000e-08</td><td>1.456228e-01</td><td>2.036000e-06</td><td>9.960000e-07</td></tr><tr><td>0.370</td><td>2.104700e-05</td><td>1.200000e-08</td><td>1.489526e-01</td><td>2.056000e-06</td><td>1.006000e-06</td></tr><tr><td><inline-formula><tex-math id="math-46"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-47"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-48"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-49"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-50"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-51"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>0.600</td><td>1.432500e-05</td><td>1.000000e-08</td><td>2.187878e-01</td><td>2.344000e-06</td><td>1.147000e-06</td></tr><tr><td>0.610</td><td>1.411100e-05</td><td>9.000000e-09</td><td>2.215725e-01</td><td>2.350000e-06</td><td>1.151000e-06</td></tr><tr><td><inline-formula><tex-math id="math-52"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-53"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-54"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-55"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-56"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-57"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>0.990</td><td>8.588000e-06</td><td>7.000000e-09</td><td>3.161976e-01</td><td>2.450000e-06</td><td>1.201000e-06</td></tr><tr><td>1.000</td><td>8.489000e-06</td><td>6.000000e-09</td><td>3.184437e-01</td><td>2.449000e-06</td><td>1.202000e-06</td></tr></tbody></table></table-wrap><p>From <xref ref-type="table" rid="table-1">Table 1</xref>, it can be seen that HM shows the highest error across all values of t, indicating that it performs the worst for this step-size. EuM and AHM progressively reduce error, with HeM consistently showing better results than HM and AHM. On the other hand, HRM demonstrates its superiority, with significantly lower error compared to the other methods. At a smaller step-size as can be viewed in <xref ref-type="table" rid="table-2">Table 2</xref>, the errors of all methods decrease significantly where HRM continues to provide consistent accuracy, followed by AHM, EuM and finally HM. As step-size decreases, the errors of all methods decreases while HRM and HeM consistently perform well.</p><p><bold>Example 3.2.</bold> Given IVP</p><disp-formula id="equation-19"><tex-math id="math-58"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \begin{array}{l} \frac {d y}{d t} = \cos (t) ^ {2} \\ y (0) = 0. \end{array}\tag{17} \end{document} ]]></tex-math></disp-formula><p>The exact solution is <inline-formula><tex-math id="math-59"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y ( t ) = \frac { t } { 2 } + \frac { \sin ( 2 \cdot t ) } { 4 } , 0 \leq t \leq 1 0 \end{document} ]]></tex-math></inline-formula> . The following tables present the numerical solutions for <inline-formula><tex-math id="math-60"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \bar { h _ { } } = 0 . 1 \end{document} ]]></tex-math></inline-formula> and <inline-formula><tex-math id="math-61"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle h = 0 . 0 1 \end{document} ]]></tex-math></inline-formula></p><p><xref ref-type="table" rid="table-3">Table 3</xref> presents the results in which HRM again shows a consistent accuracy across the entire time range. HM performs poorly with the largest errors among all methods while EuM, HeM, and AHM performs moderately, with AHM closer to HRM in accuracy. At smaller the step-size, as can be seen in <xref ref-type="table" rid="table-5">Table 5</xref>, the errors across all methods reduce and HRM maintains the consistency despite not as accurate as EuM and HeM.</p><table-wrap id="table-3"><label>Table 3</label><caption><p>Error comparison of EuM, HeM, HM, AHM, and HRM for IVP <xref ref-type="disp-formula" rid="equation-19">(17)</xref> with h = 0. 1</p></caption><table><colgroup><col></col><col></col><col></col><col></col><col></col><col></col></colgroup><thead><tr><th scope="col">t</th><th scope="col">EuM</th><th scope="col">HeM</th><th scope="col">HM</th><th scope="col">AHM</th><th scope="col">HRM</th></tr></thead><tbody><tr><td>0.100</td><td>3.326673e-04</td><td>1.656682e-04</td><td>4.991525e-02</td><td>1.644204e-04</td><td>1.662922e-04</td></tr><tr><td>0.200</td><td>1.149784e-03</td><td>3.247318e-04</td><td>9.882725e-02</td><td>3.123280e-04</td><td>3.309341e-04</td></tr><tr><td>0.300</td><td>1.916083e-03</td><td>4.708494e-04</td><td>1.457728e-01</td><td>4.278717e-04</td><td>4.923411e-04</td></tr><tr><td><inline-formula><tex-math id="math-62"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-63"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-64"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-65"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-66"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-67"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>3.500</td><td>1.322168e-03</td><td>5.478540e-04</td><td>9.502217e-01</td><td>6.627667e-03</td><td>4.232565e-03</td></tr><tr><td>3.600</td><td>7.077680e-04</td><td>6.618310e-04</td><td>9.922851e-01</td><td>6.592451e-03</td><td>4.385941e-03</td></tr><tr><td>3.700</td><td>2.284330e-04</td><td>7.494230e-04</td><td>1.030341e+00</td><td>6.623149e-03</td><td>4.532724e-03</td></tr><tr><td><inline-formula><tex-math id="math-68"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-69"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-70"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-71"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-72"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-73"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>9.900</td><td>7.923435e-03</td><td>6.785120e-04</td><td>2.555563e+00</td><td>2.080711e-02</td><td>1.171755e-02</td></tr><tr><td>10.000</td><td>7.469339e-03</td><td>7.612940e-04</td><td>2.592888e+00</td><td>2.084982e-02</td><td>1.186313e-02</td></tr></tbody></table></table-wrap><table-wrap id="table-4"><label>Table 4</label><caption><p>Error comparison of EuM, HeM, HM, AHM, and HRM for IVP <xref ref-type="disp-formula" rid="equation-19">(17)</xref> with h = 0.01</p></caption><table><colgroup><col></col><col></col><col></col><col></col><col></col><col></col></colgroup><thead><tr><th scope="col">t</th><th scope="col">EuM</th><th scope="col">HeM</th><th scope="col">HM</th><th scope="col">AHM</th><th scope="col">HRM</th></tr></thead><tbody><tr><td>0.010</td><td>3.333280e-07</td><td>1.666570e-07</td><td>4.999917e-03</td><td>1.666420e-07</td><td>1.666620e-07</td></tr><tr><td>0.020</td><td>1.166490e-06</td><td>3.332500e-07</td><td>9.998833e-03</td><td>3.331300e-07</td><td>3.333100e-07</td></tr><tr><td>0.030</td><td>1.999150e-06</td><td>4.997000e-07</td><td>1.499575e-02</td><td>4.992700e-07</td><td>4.999200e-07</td></tr><tr><td><inline-formula><tex-math id="math-74"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-75"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-76"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-77"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-78"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-79"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>0.210</td><td>1.646610e-05</td><td>3.398000e-06</td><td>1.034716e-01</td><td>3.245000e-06</td><td>3.474400e-06</td></tr><tr><td>0.220</td><td>1.721730e-05</td><td>3.549500e-06</td><td>1.082440e-01</td><td>3.373700e-06</td><td>3.637300e-06</td></tr><tr><td><inline-formula><tex-math id="math-80"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-81"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-82"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-83"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-84"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-85"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>1.630</td><td>2.505830e-05</td><td>9.843000e-07</td><td>3.926916e-01</td><td>4.250750e-05</td><td>1.989780e-05</td></tr><tr><td>1.640</td><td>2.613520e-05</td><td>1.149500e-06</td><td>3.927117e-01</td><td>4.316770e-05</td><td>1.998150e-05</td></tr><tr><td><inline-formula><tex-math id="math-86"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-87"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-88"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-89"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-90"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-91"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>3.600</td><td>6.997000e-06</td><td>6.620000e-06</td><td>9.991324e-01</td><td>7.274200e-05</td><td>4.642200e-05</td></tr><tr><td>3.610</td><td>6.537000e-06</td><td>6.720000e-06</td><td>1.003133e+00</td><td>7.274200e-05</td><td>4.657200e-05</td></tr><tr><td><inline-formula><tex-math id="math-92"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-93"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-94"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-95"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-96"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-97"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>4.440</td><td>2.977400e-05</td><td>4.322000e-06</td><td>1.174677e+00</td><td>9.948100e-05</td><td>5.634300e-05</td></tr><tr><td>4.450</td><td>3.071700e-05</td><td>4.178000e-06</td><td>1.175025e+00</td><td>1.000900e-04</td><td>5.643200e-05</td></tr><tr><td><inline-formula><tex-math id="math-98"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-99"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-100"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-101"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-102"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-103"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>9.640</td><td>1.001590e-04</td><td>3.483000e-06</td><td>2.461928e+00</td><td>2.299690e-04</td><td>1.205780e-04</td></tr><tr><td>9.650</td><td>9.941200e-05</td><td>3.634000e-06</td><td>2.466689e+00</td><td>2.298420e-04</td><td>1.207410e-04</td></tr><tr><td><inline-formula><tex-math id="math-104"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-105"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-106"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-107"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-108"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-109"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>9.990</td><td>8.088600e-05</td><td>7.544000e-06</td><td>2.610343e+00</td><td>2.285630e-04</td><td>1.259710e-04</td></tr><tr><td>10.000</td><td>8.060000e-05</td><td>7.614000e-06</td><td>2.613886e+00</td><td>2.286390e-04</td><td>1.261130e-04</td></tr></tbody></table></table-wrap><table-wrap id="table-5"><label>Table 5</label><caption><p>Error comparison of EuM, HeM, HM, AHM, and HRM for IVP <xref ref-type="disp-formula" rid="equation-19">(17)</xref> with <inline-formula><tex-math id="math-110"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle h = 0 . 0 1 \end{document} ]]></tex-math></inline-formula></p></caption><table><colgroup><col></col><col></col><col></col><col></col><col></col><col></col></colgroup><thead><tr><th scope="col">t</th><th scope="col">EuM</th><th scope="col">HeM</th><th scope="col">HM</th><th scope="col">AHM</th><th scope="col">HRM</th></tr></thead><tbody><tr><td>0.010</td><td>3.333280e-07</td><td>1.666570e-07</td><td>4.999917e-03</td><td>1.666420e-07</td><td>1.666620e-07</td></tr><tr><td>0.020</td><td>1.166490e-06</td><td>3.332500e-07</td><td>9.998833e-03</td><td>3.331300e-07</td><td>3.333100e-07</td></tr><tr><td>0.030</td><td>1.999150e-06</td><td>4.997000e-07</td><td>1.499575e-02</td><td>4.992700e-07</td><td>4.999200e-07</td></tr><tr><td><inline-formula><tex-math id="math-111"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-112"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-113"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-114"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-115"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-116"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>0.210</td><td>1.646610e-05</td><td>3.398000e-06</td><td>1.034716e-01</td><td>3.245000e-06</td><td>3.474400e-06</td></tr><tr><td>0.220</td><td>1.721730e-05</td><td>3.549500e-06</td><td>1.082440e-01</td><td>3.373700e-06</td><td>3.637300e-06</td></tr><tr><td><inline-formula><tex-math id="math-117"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-118"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-119"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-120"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-121"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-122"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>1.630</td><td>2.505830e-05</td><td>9.843000e-07</td><td>3.926916e-01</td><td>4.250750e-05</td><td>1.989780e-05</td></tr><tr><td>1.640</td><td>2.613520e-05</td><td>1.149500e-06</td><td>3.927117e-01</td><td>4.316770e-05</td><td>1.998150e-05</td></tr><tr><td><inline-formula><tex-math id="math-123"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-124"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-125"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-126"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-127"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-128"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>3.600</td><td>6.997000e-06</td><td>6.620000e-06</td><td>9.991324e-01</td><td>7.274200e-05</td><td>4.642200e-05</td></tr><tr><td>3.610</td><td>6.537000e-06</td><td>6.720000e-06</td><td>1.003133e+00</td><td>7.274200e-05</td><td>4.657200e-05</td></tr><tr><td><inline-formula><tex-math id="math-129"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-130"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-131"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-132"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-133"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-134"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>4.440</td><td>2.977400e-05</td><td>4.322000e-06</td><td>1.174677e+00</td><td>9.948100e-05</td><td>5.634300e-05</td></tr><tr><td>4.450</td><td>3.071700e-05</td><td>4.178000e-06</td><td>1.175025e+00</td><td>1.000900e-04</td><td>5.643200e-05</td></tr><tr><td><inline-formula><tex-math id="math-135"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-136"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-137"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-138"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-139"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-140"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>9.640</td><td>1.001590e-04</td><td>3.483000e-06</td><td>2.461928e+00</td><td>2.299690e-04</td><td>1.205780e-04</td></tr><tr><td>9.650</td><td>9.941200e-05</td><td>3.634000e-06</td><td>2.466689e+00</td><td>2.298420e-04</td><td>1.207410e-04</td></tr><tr><td><inline-formula><tex-math id="math-141"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-142"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-143"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-144"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-145"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-146"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>9.990</td><td>8.088600e-05</td><td>7.544000e-06</td><td>2.610343e+00</td><td>2.285630e-04</td><td>1.259710e-04</td></tr><tr><td>10.000</td><td>8.060000e-05</td><td>7.614000e-06</td><td>2.613886e+00</td><td>2.286390e-04</td><td>1.261130e-04</td></tr></tbody></table></table-wrap><p><bold>Example 3.3.</bold> The exact solution of IVP</p><disp-formula id="equation-20"><tex-math id="math-147"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle {\frac {d y}{d x}} = x ^ {2} + y x\tag{18} \end{document} ]]></tex-math></disp-formula><disp-formula id="equation-21"><tex-math id="math-148"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y (0) = 1 \end{document} ]]></tex-math></disp-formula><p>is <inline-formula><tex-math id="math-149"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle y ( x ) = - x + { \frac { \mathrm { e } ^ { \frac { x ^ { 2 } } { 2 } } \cdot { \sqrt { \pi } } \cdot { \sqrt { 2 } } \cdot \mathrm { e r f } \left( { \frac { { \sqrt { 2 } } \cdot x } { 2 } } \right) } { 2 } } + \mathrm { e } ^ { \frac { x ^ { 2 } } { 2 } } \end{document} ]]></tex-math></inline-formula> . The tables below presents the errors given by the mentioned methods for 0 ≤ t ≤ 1.</p><table-wrap id="table-6"><label>Table 6</label><caption><p>Error comparison of EuM, HeM, HM, AHM, and HRM for IVP <xref ref-type="disp-formula" rid="equation-20">(18)</xref> with h = 0.1</p></caption><table><colgroup><col></col><col></col><col></col><col></col><col></col><col></col></colgroup><thead><tr><th scope="col">t</th><th scope="col">EuM</th><th scope="col">HeM</th><th scope="col">HM</th><th scope="col">AHM</th><th scope="col">HRM</th></tr></thead><tbody><tr><td>0.100</td><td>5.346522e-03</td><td>1.534781e-04</td><td>1.534781e-04</td><td>2.903478e-03</td><td>1.457435e-03</td></tr><tr><td>0.200</td><td>7.961484e-03</td><td>3.035877e-04</td><td>7.297711e-03</td><td>4.342679e-03</td><td>1.974052e-03</td></tr><tr><td>0.300</td><td>9.858246e-03</td><td>4.478703e-04</td><td>2.249504e-02</td><td>5.573349e-03</td><td>2.385002e-03</td></tr><tr><td>0.400</td><td>1.192778e-02</td><td>5.816589e-04</td><td>4.699446e-02</td><td>6.806972e-03</td><td>2.813163e-03</td></tr><tr><td>0.500</td><td>1.436895e-02</td><td>6.970676e-04</td><td>8.294958e-02</td><td>8.138060e-03</td><td>3.319746e-03</td></tr><tr><td>0.600</td><td>1.734100e-02</td><td>7.815183e-04</td><td>1.331632e-01</td><td>9.634144e-03</td><td>3.958304e-03</td></tr><tr><td>0.700</td><td>2.102439e-02</td><td>8.155925e-04</td><td>2.012491e-01</td><td>1.135848e-02</td><td>4.790266e-03</td></tr><tr><td>0.800</td><td>2.564585e-02</td><td>7.698856e-04</td><td>2.918645e-01</td><td>1.337946e-02</td><td>5.894602e-03</td></tr><tr><td>0.900</td><td>3.150123e-02</td><td>6.004090e-04</td><td>4.110245e-01</td><td>1.577656e-02</td><td>7.377777e-03</td></tr><tr><td>1.000</td><td>3.898340e-02</td><td>2.418500e-04</td><td>5.665221e-01</td><td>1.864557e-02</td><td>9.386511e-03</td></tr></tbody></table></table-wrap><table-wrap id="table-7"><label>Table 7</label><caption><p>Error comparison of EuM, HeM, HM, AHM, and HRM for IVP (18) with h = 0.01</p></caption><table><colgroup><col></col><col></col><col></col><col></col><col></col><col></col></colgroup><thead><tr><th scope="col">t</th><th scope="col">EuM</th><th scope="col">HeM</th><th scope="col">HM</th><th scope="col">AHM</th><th scope="col">HRM</th></tr></thead><tbody><tr><td>0.010</td><td>5.033433e-05</td><td>1.656700e-07</td><td>1.656700e-07</td><td>2.541567e-05</td><td>1.462533e-05</td></tr><tr><td>0.020</td><td>6.597387e-05</td><td>3.311300e-07</td><td>6.722887e-05</td><td>3.428413e-05</td><td>1.892887e-05</td></tr><tr><td><inline-formula><tex-math id="math-150"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-151"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-152"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-153"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-154"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-155"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>0.060</td><td>8.032384e-05</td><td>9.921600e-07</td><td>8.875078e-04</td><td>5.019116e-05</td><td>2.594084e-05</td></tr><tr><td>0.070</td><td>8.260844e-05</td><td>1.157560e-06</td><td>1.232278e-03</td><td>5.271456e-05</td><td>2.695844e-05</td></tr><tr><td><inline-formula><tex-math id="math-156"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-157"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-158"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-159"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-160"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-161"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>0.180</td><td>1.034335e-04</td><td>2.968500e-06</td><td>9.107826e-03</td><td>7.195850e-05</td><td>3.389950e-05</td></tr><tr><td>0.190</td><td>1.052670e-04</td><td>3.131000e-06</td><td>1.022915e-02</td><td>7.339500e-05</td><td>3.437800e-05</td></tr><tr><td><inline-formula><tex-math id="math-162"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-163"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-164"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-165"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-166"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-167"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>0.510</td><td>1.810713e-04</td><td>7.949700e-06</td><td>9.541977e-02</td><td>1.202127e-04</td><td>5.084630e-05</td></tr><tr><td>0.520</td><td>1.842819e-04</td><td>8.071100e-06</td><td>1.000552e-01</td><td>1.219251e-04</td><td>5.153390e-05</td></tr><tr><td><inline-formula><tex-math id="math-168"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-169"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-170"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-171"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-172"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td><td><inline-formula><tex-math id="math-173"><![CDATA[ \documentclass{article} \usepackage{amsmath} \begin{document} \displaystyle \vdots \end{document} ]]></tex-math></inline-formula></td></tr><tr><td>0.980</td><td>4.513070e-04</td><td>5.488000e-06</td><td>5.541857e-01</td><td>2.418560e-04</td><td>1.164820e-04</td></tr><tr><td>0.990</td><td>4.611220e-04</td><td>5.067000e-06</td><td>5.716989e-01</td><td>2.457660e-04</td><td>1.191060e-04</td></tr><tr><td>1.000</td><td>4.711920e-04</td><td>4.618000e-06</td><td>5.896761e-01</td><td>2.497540e-04</td><td>1.218120e-04</td></tr></tbody></table></table-wrap><p>Similar to previous examples, HRM still provides the smallest errors, after HeM. At this step-size, HM shows the largest error values, followed by EuM and AHM, as seen in Table 6. Reducing the step-size for this example, results in improved accuracy of all methods, but the ranking remains consistent which is apparent in <xref ref-type="table" rid="table-7">Table 7</xref>.</p><p>Overall, from the results of the numerical simulations, HRM shows the best performance in terms of accuracy. It consistently has the smallest error for both large end small step-size. HRM can also handle larger step-size without sacrificing much accuracy, unlike HM, which performs poorly with large step-size. In addition, HRM works well for diferent types of diferential equations as demonstrated across all examples. This shows the versatility of HRM and marks consistency of the method for solving IVPs that require precise solutions.</p></sec><sec id="sec-7"><title>4. CONCLUSIONS</title><p>This paper introduces a novel numerical technique for solving initial value problems (IVPs) by modifying Heun’s method. The modification involves using the harmonic and root mean square to calculate the average of the slopes of the tangents in Heun’s method. Stability and consistency analyses demonstrate the reliability of the approach, while numerical simulations emphasize its accuracy in producing approximate solutions with improved precision. The proposed method shows competitive potential compared to existing methods, ofering a viable alternative for solving IVPs. Future advancements could involve applying other averaging techniques to diferent numerical methods, expanding their use for solving real-world problems.</p></sec></body><back><sec sec-type="data-availability"><title>Data Availability Statement.</title><p>No new data were created or analyzed in this study.</p></sec><sec sec-type="author-contributions"><title>Author Contributions.</title><p>All authors have read and agreed to the published version of the manuscript. All authors contributed equally to this paper. All authors reviewed the manuscript.</p></sec><ack><title>Acknowledgement.</title><p>The authors gratefully acknowledge the financial support provided by the Institute for Research and Community Service (LPPM), Universitas Riau, which has been instrumental in the successful completion of this research.</p></ack><ref-list><title>REFERENCES</title><ref id="BIBR-1"><element-citation publication-type="journal"><article-title>Improving the eficiency of heun’s method</article-title><source>Sindh University Research Journal-SURJ (Science</source><volume>42</volume><issue>2</issue><person-group person-group-type="author"><name><surname>Chandio</surname><given-names>M.</given-names></name><name><surname>Memon</surname><given-names>A.</given-names></name><etal/></person-group><year>2010</year><ext-link xlink:href="https://nja.pastic.gov.pk/" ext-link-type="uri" xlink:title="Website link">Website link</ext-link></element-citation></ref><ref id="BIBR-2"><element-citation publication-type="book"><article-title>Advanced engineering mathematics 9th edition with Wiley plus set</article-title><volume>334</volume><person-group person-group-type="author"><name><surname>Kreyszig</surname><given-names>E.</given-names></name></person-group><year>2007</year><publisher-name>John Wiley &amp; Sons US</publisher-name></element-citation></ref><ref id="BIBR-3"><element-citation publication-type="journal"><article-title>An eficient third-order scheme based on runge–kutta and taylor series expansion for solving initial value problems</article-title><source>Algorithms</source><volume>17</volume><issue>3</issue><person-group person-group-type="author"><name><surname>Abdul-Hassan</surname><given-names>N.Y.</given-names></name><name><surname>Kadum</surname><given-names>Z.J.</given-names></name><name><surname>Ali</surname><given-names>A.H.</given-names></name></person-group><year>2024</year><page-range>123,</page-range><pub-id pub-id-type="doi">10.3390/a17030123</pub-id></element-citation></ref><ref id="BIBR-4"><element-citation publication-type="journal"><article-title>New numerical methods for solving the initial value problem based on a symmetrical quadrature integration formula using hybrid functions</article-title><source>Symmetry</source><volume>15</volume><issue>3</issue><person-group person-group-type="author"><name><surname>Kadum</surname><given-names>Z.J.</given-names></name><name><surname>Abdul-Hassan</surname><given-names>N.Y.</given-names></name></person-group><year>2023</year><page-range>631,</page-range><pub-id pub-id-type="doi">10.3390/sym15030631</pub-id></element-citation></ref><ref id="BIBR-5"><element-citation publication-type="journal"><article-title>A numerical solver for first order initial value problems of ordinary diferential equation via the combination of chebyshev polynomial and exponential function</article-title><source>Journal of Physical Sciences</source><volume>1</volume><issue>1</issue><person-group person-group-type="author"><name><surname>Ogunrinde</surname><given-names>R.</given-names></name><name><surname>Olayemi</surname><given-names>K.</given-names></name><name><surname>Isah</surname><given-names>I.</given-names></name><name><surname>Salawu</surname><given-names>A.</given-names></name></person-group><year>2019</year><page-range>1-16,</page-range><pub-id pub-id-type="doi">10.1155/2020/6650855</pub-id></element-citation></ref><ref id="BIBR-6"><element-citation publication-type="journal"><article-title>New modification on heun’s method based on contraharmonic mean for solving initial value problems with high eficiency</article-title><source>Journal of Mathematics</source><issue>1</issue><person-group person-group-type="author"><name><surname>Workie</surname><given-names>A.H.</given-names></name></person-group><year>2020</year><page-range>6650855,</page-range><ext-link xlink:href="https://scispace.com/pdf/" ext-link-type="uri" xlink:title="Pdf">Pdf</ext-link></element-citation></ref><ref id="BIBR-7"><element-citation publication-type="journal"><article-title>A hybrid numerical method with greater eficiency for solving initial value problems</article-title><source>Mathematical Theory and Modeling</source><volume>10</volume><issue>2</issue><person-group person-group-type="author"><name><surname>Ram</surname><given-names>T.</given-names></name><name><surname>Solangi</surname><given-names>M.A.</given-names></name><name><surname>Sanghah</surname><given-names>A.A.</given-names></name></person-group><year>2020</year><page-range>1-7,</page-range><ext-link xlink:href="https://iiste.org/Journals/index.php/MTM/article/view/51759" ext-link-type="uri" xlink:title="51759">51759</ext-link></element-citation></ref><ref id="BIBR-8"><element-citation publication-type="journal"><article-title>A third order runge-kutta method based on a convex combination of lehmer means</article-title><source>J. 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